Answer:
[H⁺] = 1.58 x 10⁻⁷ M.
Explanation:
∵ pOH = - log[OH⁻]
7.20 = - log[OH⁻]
log[OH⁻] = - 7.20
∴ [OH⁻] = 6.31 x 10⁻⁸.
∵ [H⁺][OH⁻] = 10⁻¹⁴.
∴ [H⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(6.31 x 10⁻⁸) = 1.585 x 10⁻⁷ M.
Answer is: A. 1.81 mol.
Balanced chemical reaction: FeCl₂ + 2KOH → Fe(OH)₂ + 2KCl.
n(FeCl₂) = 4.15 mol; amount of iron(II) chloride.
n(KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.
From chemical reaction: n(KOH) : n(Fe(OH)₂) = 2 : 1.
n(Fe(OH)₂) = n(KOH) ÷ 2.
n(Fe(OH)₂) = 3.62 mol ÷ 2.
n(Fe(OH)₂) = 1.81 mol; amount of iron(II) hydroxide.
<h3>Answer:</h3>
Platoic Acid
<h3>Explanation:</h3>
While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.
Examples:
HCOOH → HCOO⁻ + H⁺
Formic acid Formate Ion
H₃CCOOH → H₃CCOO⁻ + H⁺
Acetic acid Acetate Ion
H₅C₂COOH → H₅C₂COO⁻ + H⁺
Propanoic acid Propanoate Ion
Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid <em>i.e.</em>
RCOO⁻ + H⁺ → RCOOH
Platoate Ion Platoic Acid
It matches the universal pH indicator and is indicating the proper pH
Molarity is one of the method of expressing concentration of solution. Mathematically it is expressed as,
Molarity =
Given: Molarity of solution = 5.00 M
Volume of solution = 750 ml = 0.750 l
∴ 5 =
∴
number of moles = 3.75Answer: Number of moles of KOH present in solution is 3.75.
