Answer:
b
Explanation:
The reaction that is not a displacement reaction from all the options is 
In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.
<em>Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.</em>
Correct option = b.
<span>The difference in pressure is equal to the pressure exerted by the displaced fluid.
Since the Pressure difference is equal, density of fluid is inversely proportional to the height of the column of displaced fluid => (Ď1)(h1) = (Ď2)(h2)
(13.6 g/ml)(753 - 724 mm Hg) = (0.822 g/ml)(h2)
h2 = (13.6 g/ml)(753 - 724 mm Hg) / (0.822 g/ml)
h2 = 480 mm</span>
Answer:
- <em>The unknown integer X in the formula is </em><u>5</u><em>.</em>
Explanation:
<u>1) Data:</u>
a) Mass of CuSO₄ ∙ XH₂O = 1.50 g
b) Mass of CuSO₄ = 0.96
c) X = ?
<u>2) Additional needed data:</u>
a) Molar Mass of CuSO₄ = 159,609 g/mol
b) Molar mass of H₂O = 18,01528 g/mol
<u>3) Chemical principles and formulae used:</u>
a) Law of conservation of mass
b) Molar mass = mass in grams / number of moles = m / n
<u>4) Solution:</u>
a) Law of conservation of mass:
- Mass of CuSO₄ ∙ XH₂O = mass of CuSO₄ + mass of H₂O
- 1.50g = 0.96g + mass of H₂O ⇒ mass of H₂O = 1.50g - 0.96g = 0.54g
b) Moles
- CuSO₄: n = 0.96g / 159.609 g/mol = 0.0060 mol
- H₂O: 0.54g / 18.01528 g/mol = 0.030 mol
c) Proportion:
Divide both mole amounts by the least of the two numbers, i.e. 0.0060
- CuSO₄: 0.0060 / 0.0060 = 1
- H₂O: 0.030 mol / 0.0060 = 5
Then, the ratio of CuSO₄ to H₂O is 1 : 5 and the chemical formula is:
Hence, the value of X is 5.
N=3.5 mol
c=3.5 mol/L
n=cv
v=n/c
v=3.5/3.5=1.0 L
A) 1.0 liter of solution
