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VLD [36.1K]
2 years ago
6

Tell whether the following pairs of compounds are identical, constitutional isomers, stereoisomers, or unrelated. (a) cis-1,3-Di

bromocyclohexane and trans-1,4-dibromocyclohexane (b) 2,3-Dimethylhexane and 2,3,3-trimethylpentane
Chemistry
1 answer:
Aleks04 [339]2 years ago
7 0

Answer:

     (a) Constitutional Isomers

     (b) Constitutional Isomers

Explanation:

Constitutional isomers are also known with the name Structural Isomers. These are the compounds which have same chemical formula but differ in arrangement of atoms i.e. structure.

Both the compounds <em>cis-1,3-dibromocyclohexane</em> and <em>trans-1,4-dibromocyclohexane</em> have the same chemical formula C_{6} H_{10} Br_{2} but have different structure as shown in the image below.

In the second case the compounds <em>2,3-dimethylhexane</em> and <em>2,3,3-trimethylpentane</em>, both have same chemical formula C_{8} H_{18} but have different structures which is shown in the image below.

Thus it is clear that in both the groups (a) and (b) the given compounds are Constitutional Isomers.

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In a hexagonal-close-pack (hcp) unit cell, the ratio of lattice points to octahedral holes to tetrahedral holes is 1:1:2. What i
Alex777 [14]

Explanation:

In a hexagonal-close-pack (HCP) unit cell, the ratio of lattice points to octahedral holes to tetrahedral holes =  1 : 1 : 2

let the :

Number of lattice point = 1x.

Number of octahedral points = 1x

Number of tetrahedral  points = 2x

If anions occupy the HCP lattice points and cations occupy half of the tetrahedral holes.

Number of anions occupying the HCP lattice points, A= 1x

Number of cations occupying the tetrahedral points, B =  \frac{2x}{2}=x

The formula of the compound will be = A_{1x}B_{1x}=AB

If anions occupy the HCP lattice points and cations occupy all of the tetrahedral holes.

Number of anions occupying the HCP lattice points, A= 1x

Number of cations occupying the tetrahedral points, B =  2x

The formula of the compound will be = A_{1x}B_{2x}=AB_2

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2 years ago
Berny has a 0.15-kilogram candle, a 1.00-kilogram jar, and a 0.25 kilogram candle holder. He places the candle and candle holder
Kobotan [32]
It's a because if you add them together you till get 1.40
5 0
2 years ago
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A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solu
irinina [24]

Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = 6.05\times 10^3 kg=6.05\times 10^6 g

1 kg = 10^3 g

Percentage mass of sulfuric acid = 95.0%

Mass of sulfuric acid = \frac{95.0}{100}\times 6.05\times 10^6 g

=5,747,500 g

Moles of sulfuric acid = \frac{5,747,500 g}{98 g/mol}=58,647.96 mol

H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

\frac{1}{1}\times 58,647.96 mol=58,647.96 mol of sodium carbonate

Mass of 58,647.96 moles of sodium carbonate :

106 g/mol\times 58,647.96 mol=6,216,683.76 g

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg

6,216.684 kilograms of sodium carbonate must be added to neutralize 6.05\times 10^3 kg of sulfuric acid solution.

3 0
2 years ago
Which statement correctly describes a sample of gas confined in a sealed container? (1) It always has a definite volume, and it
Luda [366]
A gas does not have a specific shape or volume (so we reject option A), instead it adjusts itself to the container (which is further influenced by other forces such as gravity and temperature) and it with time, willl fill the whole container evenly, so the correct answer is:
(2) It takes the shape and the volume of any container in which it is confined
5 0
2 years ago
How many inner, outer, and valence electrons are present in an atom of each of the following elements?
Aneli [31]

<u>Answer:</u>

<u>For a:</u> The number of inner electrons, outer electrons and valence electrons are 28, 7 and 7 respectively.

<u>For b:</u> The number of inner electrons, outer electrons and valence electrons are 54, 1 and 1 respectively.

<u>For c:</u> The number of inner electrons, outer electrons and valence electrons are 23, 1 and 1 respectively.

<u>For d:</u> The number of inner electrons, outer electrons and valence electrons are 36, 2 and 2 respectively.

<u>For e:</u> The number of inner electrons, outer electrons and valence electrons are 2, 7 and 7 respectively.

<u>Explanation:</u>

Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons. The electrons present in the highest principle quantum number are known as valence electrons.

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Inner electrons = Total number of electrons - Valence electrons

Total number of electrons in an atom is equal to the atomic number of the element.

For the given options:

  • <u>Option a:</u>  Bromine (Br)

Bromine is the 35th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Highest principle quantum number is 4

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 35 - 7 = 28

  • <u>Option b:</u>  Cesium (Cs)

Cesium is the 55th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^1

Highest principle quantum number is 6

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 55 - 1 = 54

  • <u>Option c:</u>  Chromium (Cr)

Chromium is the 24th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^13d^{5}

Highest principle quantum number is 4

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 24 - 1 = 23

  • <u>Option d:</u>  Strontium (Sr)

Strontium is the 38th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2

Highest principle quantum number is 5

Number of valence electrons = 2

Number of outer electrons = 2

Number of inner electrons = 38 - 2 = 36

  • <u>Option e:</u>  Fluorine (F)

Fluorine is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

Highest principle quantum number is 2

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 9 - 7 = 2

4 0
2 years ago
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