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2 years ago

By which process is a precipitate most easily separated from the liquid in which it is suspended

Chemistry

2 answers:

Gelneren [198K]2 years ago

7 0

Filtration, if its a precipitate that means its insoluble.

nikitadnepr [17]2 years ago

3 0

Answer: Filtration

Explanation:

Filtration can be defined as the various mechanical, physical or biological operations that separates a solid from the liquid by adding a membrane in between which only allows the movement of liquid from it.

The precipitate is left on the membrane and the liquid is passed on into the vessels. The left over part is solid called precipitate.

Hence, the correct answer is Filtration.

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Consider the formation of nitryl fluoride: 2NO2(g)+F2(g)⇌2NO2F(g) The reaction is first order in F2 and second order overall. Wh

Dahasolnce [82]

Answer:

Rate = $k[NO_{2}][F_{2}]$

Explanation:

Two reactants are present in this reaction which are $NO_{2}and F_{2}$
We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.
Here, overall order of reaction is 2 including first order with respect to $F_{2}$
So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to $NO_{2}$
So, rate law: rate = $k[NO_{2}][F_{2}]$

7 0

2 years ago

The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of

AlexFokin [52]

Answer: C. 25.6 kPa

Explanation:

The Gauge pressure is defined as the amount of pressure in a fluid that exceeds the amount of pressure in the atmosphere.

As such, the formula will be,

PG = PT – PA

Where,

PG is Gauge Pressure

PT is Absolute Pressure

PA is Atmospheric Pressure

Inputted in the formula,

PG = 125.4 - 99.8

PG = 25.6 kPa

The gauge pressure inside the container is 25.6kPa which is option C.

4 0

2 years ago

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = -20.5 kJ/mol?

harina [27]

Answer:

Q= 245 =2.5 * 10^2

Explanation:

ΔG = ΔGº + RTLnQ, so also ΔGº= - RTLnK

R= 8,314 J/molK, T=298K

ΔGº= - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

ΔG = ΔGº + RTLnQ → -20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol* LnQ

→ 5.5 = LnQ → Q= 245 =2.5 * 10^2

6 0

2 years ago

Select all of the correct statements pertaining to the first and second ionization energies of different elements. check all tha

sertanlavr [38]

The First Ionization energy of Nitrogen is greater (Not smaller)than that of Phosphorous. This is because going down the group (N and P are in same group) the number of shells increases, the distance of valence electrons from Nucleus increases and hence due to less interaction between nucleus and valence electrons it becomes easy to knock out the electron.

The second ionization energy of Na is larger than that of Mg because after first loss of electron Na has gained Noble Gas Configuration (Stable Configuration) and now requires greater energy to loose both second electron and Noble Gas Configuration. While Mg after second ionization attains Noble Gas Configuration hence it prices less energy.

8 0

2 years ago

Read 2 more answers

Functional group and bond hybridization of vanillin

lana66690 [7]

Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group: R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a sp² hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a sp³ hybridization because they are involved only in single bonds.

7 0

2 years ago