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Kazeer [188]
2 years ago
7

Consider the formation of nitryl fluoride: 2NO2(g)+F2(g)⇌2NO2F(g) The reaction is first order in F2 and second order overall. Wh

at is the rate law? View Available Hint(s) Consider the formation of nitryl fluoride: The reaction is first order in and second order overall. What is the rate law? rate=k[NO2]2[F2]2 rate=k[NO2][F2]2 rate=k[F2] rate=k[NO2] rate=k[NO2][F2] rate=k[NO2]2[F2]
Chemistry
1 answer:
Dahasolnce [82]2 years ago
7 0

Answer:

Rate = k[NO_{2}][F_{2}]

Explanation:

  • Two reactants are present in this reaction which are NO_{2}and F_{2}
  • We know overall order of a reaction is summation of individual order with respect to reactants present in rate law equation.
  • Here, overall order of reaction is 2 including first order with respect to F_{2}
  • So, rate of reaction should also be first order with respect to another reactant i.e. first order with respect to NO_{2}
  • So, rate law: rate = k[NO_{2}][F_{2}]
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200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4

3) convert moles of CuSO₄ to moles of Cu

1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu

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I did it step-by-step as the explanation but you can do all of this in one step. 

200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu


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