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solniwko [45]
2 years ago
8

In the following reaction, identify the oxidized species, reduced species, oxidizing agent, and reducing agent. Be sure to answe

r all parts. Cl2(aq) + 2 KI(aq) → 2 KCl(aq) +12(aq) Cl, is the (select) KI is the (select) and the (select) and the (select) A. A.
Chemistry
1 answer:
gtnhenbr [62]2 years ago
7 0

Answer :

Cl_2 is reduced species.

KI is oxidized species.

Cl_2 is oxidizing agent.

KI is reducing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

Cl_2(aq)+2KI(aq)\rightarrow 2KCl(aq)+I_2(aq)

The half oxidation-reduction reactions are:

Oxidation reaction : 2I^-\rightarrow I_2+2e^-

Reduction reaction : Cl_2^++2e^-\rightarrow 2Cl^-

From this we conclude that the 'KI' is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and 'Cl_2' is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, Cl_2 is reduced species.

KI is oxidized species.

Cl_2 is oxidizing agent.

KI is reducing agent.

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Viktor [21]

Answer: Your friend is incorrect.

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6 0
2 years ago
Compared to micellular Compound 1, Compound 2 is structurally more rigid as a result of what type of interaction?
zimovet [89]

Answer:

D. Intramolecular covalent bond

Explanation:

Compound D is structurally more rigid  as a result of intramolecular covalent bonding. The forces that hold together atoms within a compound are greater as compared to forces holding two molecules  together (intermolecular bonding). On the other hand  Hydrogen bonds are weaker as compared to covalent bonds. Covalent bonds involve the sharing of electrons between two atoms and Hydrogen bonds are formed between a highly electronegative  atom like oxygen, Flourine,Chlorine to hydrogen.  

8 0
2 years ago
How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation? 2HBr(aq)+
Mkey [24]

Full Question:

A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)

Answer:

13.1 g K2CO3 required to neutralize spill

Explanation:

2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)

Number of moles = Volume * Molar Concentration

moles HBr= 0.42L x .45 M= 0.189 moles HBr

From the stoichiometry of the reaction;

1 mole of K2CO3 reacts  with 2 moles of HBr

1 mole = 2 mole

x mole = 0.189

x = 0.189 / 2 = 0.0945 moles

Mass = Number of moles * Molar mass

Mass = 0.0945 * 138.21  = 13.1 g

3 0
2 years ago
Perform the following
Ghella [55]

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

4 0
2 years ago
What volume of a 0.160 m solution of koh must be added to 450.0 ml of the acidic solution to completely neutralize all of the ac
inna [77]
An  acidic  solution  is 0.1M  in  HCl  and  0.2  H2so4. volume  is  equal  to  no  of  moles  divided  by  molarity.  
number  of  moles  of  HCl is  450ml x 0.1  divided  by 1000  which is equal  to 0.045 moles
volume  of  HCl   is  therefore  0.45  divided  by  0.16  which  is   2.81  litres

Number  of  moles  of  H2so4  is  450ml x 0.2  divided  by  1000  which  is  equal  to  0.09  moles
volume  of  H2SO4  IS  0.09 divided  by  0.16  which  is  equal  to  0.56 litres

4 0
2 years ago
Read 2 more answers
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