The ionic character of any compound depend on the lattice energy as well as the electronegativity of element present in that compound.
More would be the lattice energy more would be ionic nature of that compound.
The lattice energy of any compound is inversely proportional to the ionic radii cation and anion.
In given case the ionic radii of oxide in both oxides would be equal therefore the lattice energy only depend on the ionic radii of cation.
As the radii of Magnesium less then radii of lithium therefore lattice energy of Magnesium oxide would be more than lithium oxide.
Hence, MgO would be more ionic in nature than 
Answer:
14.9075 g, 28.67%, 0.11%
Explanation:
The mean concentration of calcium = summation x / frequency
= ( 14.92 + 1491 + 14.88 + 14.92 ) /4 = 14.9075 g
Standard deviation = √(summation (x - μ)² /n) = √ ( ((14.92 - 14.9075)² +(14.91 - 14.9075)² + (14.88 - 14.9075)² + ( 14.92 - 14.9075)²) / 4) = 0.0164
b) percent error = abs(14.9075 - 20.90) / 20.90 × 100 = 28.67%
c) relative standard deviation = standard deviation / mean × 100 = 0.0164 / 14.9075 × 100 = 0.11%
d) The accuracy of the measure is the measurement compared to the actual which according to the standard set by the instructor (5%error) is not very accurate because the percent error is high (28.67%) while the relative standard deviation is quite low ( 0.11%) which means the measurement precision is very high.
The student will have to redo the experiment because the experiment was not too accurate since the percent error is way higher than the set value (5%) although the precision was high.
Percentage by volume of solution is the percentage volume of solute in total volume of solution.
Volume percentage (v/v%) = volume of solute / total volume of solution x 100%
volume of solute - 16.0 mL
total volume of solution - 155 mL
v/v% = 16.0 / 155 x 100% = 10.32%
this means that in a volume of 100 mL solution, 10.32 mL is acetone.
Let's assume that both He and N₂ have ideal gas behavior.<span>
Then we can use ideal gas law,
PV = nRT
Where, P is the pressure of gas, V is the volume,
n is moles of gas, R is universal gas constant and T is the temperature in
Kelvin.
<span>The </span>P <span>and </span>V <span>are </span>same<span> for the
both gases.</span>
R is a
constant.
The only variables are n and T.
<span>Let's say temperature of </span>He<span> <span>is </span></span>T</span>₁<span> <span>and temperature of </span></span>N₂<span> <span>is </span></span>T₂.<span>
n = m/M<span> where n is
moles, m is mass and M is molar mass.</span>
Molar mass of He is 4 g/mol and molar mass of N₂ is 28 g/mol</span><span>
<span>Since mass (m) of both gases are same,</span>
moles of He = m/4
moles of N₂ = m/28</span><span>
Let's apply the ideal gas equation for both gases.
For He gas,
PV = (m/4)RT₁ </span>(1)<span>
For N</span>₂ gas,<span>
PV = (m/28)RT₂<span> </span></span> (2)<span>
(1) = (2)
</span><span>(m/4)RT₁ =
(m/28)RT₂</span> <span>
T₁/4
= T₂/28</span><span>
T₁ = T₂/7</span><span>
<span> </span>7T</span>₁ = T₂<span>
Hence, the
temperature of N</span>₂<span> gas is higher by 7
times than the temperature of He gas.</span>