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Rus_ich [418]
2 years ago
9

A student is setting up a model to study the carbon cycle and natural sources of carbon dioxide. They create a microenvironment

that contains soil, leaf debris, an earthworm, heterotrophic bacteria, and a sun lamp. What natural source of carbon dioxide and major metabolic process was left out of the model
Chemistry
1 answer:
cluponka [151]2 years ago
4 0

Fossil fuels, forest fires, and respiration and major metabolic process photosynthesis are left out of the model.                

<u>Explanation</u>:

  • The carbon cycle model contains all the activities but some points are missing in it. Oceans, the burning of fossil fuels should be explained.  Natural elements such as coal and natural gas are the main elements of the carbon cycle.
  • Because they are important compounds of the carbon cycle. The process of photosynthesis is very important in the carbon cycle. The process of volcanic eruption should be explained in the carbon cycle.        

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What is the mass of solute in 200.0 L of a 1.556-M solution of KBr
sergejj [24]
The molarity of KBr solution is 1.556 M
molarity is defined as the number of moles of solute in volume of 1 L solution.
the number of KBr moles in 1 L - 1.556 mol
Therefore in 200.0 L - 1.556 mol/L x 200.0 L = 311.2 mol
Molar mass of KBr - 119 g/mol 
mass of Kbr - 311.2 mol x 119 g/mol = 37 033 g
mass of solute therefore is 37.033 kg
4 0
1 year ago
A sample of hydrogen was collected by water displacement at 23.0°C and an atmospheric pressure of 735 mmHg. Its volume is 568 mL
ziro4ka [17]

Answer:

V = 552 mL or 0.552 L

Explanation:

First, we need to calculate the number of moles of H2 using the ideal gas equation which is:

PV = nRT

Solving for n:

n = PV / RT

Where:

P = Pressure

V = Volume

R = Gas constant (0.082 L atm / K mol)

T = Temperature in K

Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg

P = 735 / 760 = 0.967 atm

Pwater = 21 / 760 = 0.028 atm

Finally temperature to Kelvin:

T = 23 + 273.15 = 296.15 K

Now, at first the hydrogen was collected by water displacement so pressure is:

P = 0.967 - 0.028 = 0.939 atm

Now the moles of hydrogen:

n = 0.939 * 0.568 / 0.082 * 296.15

n = 0.022 moles

Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg

V = nRT/P

V = 0.022 * 0.082 * 296.15 / 0.967

V = 0.552 L or 552 mL

This is the volume that hydrogen occupies.

6 0
2 years ago
A proton transfer reaction can occur when an aldehyde is placed in strong base, such as an alkoxide ion, producing an alcohol an
Pani-rosa [81]

Hi, you have not provided structure of the aldehyde and alkoxide ion.

Therefore i'll show a mechanism corresponding to the proton transfer by considering a simple example.

Explanation: For an example, let's consider that proton transfer is taking place between a simple aldehyde e.g. acetaldehyde and a simple alkoxide base e.g. methoxide.

The hydrogen atom attached to the carbon atom adjacent to aldehyde group are most acidic. Hence they are removed by alkoxide preferably.

After removal of proton from aldehyde, a carbanion is generated. As it is a conjugated carbanion therefore the negative charge on carbon atom can conjugate through the carbonyl group to form an enolate which is another canonical form of the carbanion.

All the structures are shown below.

7 0
2 years ago
What reaction would take place if a hot tungsten filament bulb was surrounded by air
expeople1 [14]
I don't think it wont be a big explosion 
4 0
2 years ago
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Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note the
joja [24]
The first step is to balance the equation:


<span>C3H8 + 5O2 ---> 3CO2 + 4H2O


Check the balance


element          left side        right side

C                    3                  3  
H                    8                  4*2 = 8
O                    5*2=10        3*2 + 4 = 10


Then you have the molar ratios:


3 mol C3H8 : 5 mol O2 : 3 mol CO2 : 4 mol H2O


Now you have 40 moles of O2 so you make the proportion:

40.0 mol O2 * [3 mol CO2 / 5 mol O2] = 24.0 mol CO2.


Answer: option D. 24.0 mol CO2
</span>
7 0
2 years ago
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