A proton transfer reaction can occur when an aldehyde is placed in strong base, such as an alkoxide ion, producing an alcohol an
d a charged conjugate base that is resonance stabilized. In the left box, draw the curved arrows for the proton transfer. In the middle and right boxes, draw the two structures for the resonance-stabilized product as noted in the box-specific directions. Be sure to include all lone pairs and nonzero formal charges.
1 answer:
Hi, you have not provided structure of the aldehyde and alkoxide ion.
Therefore i'll show a mechanism corresponding to the proton transfer by considering a simple example.
Explanation: For an example, let's consider that proton transfer is taking place between a simple aldehyde e.g. acetaldehyde and a simple alkoxide base e.g. methoxide.
The hydrogen atom attached to the carbon atom adjacent to aldehyde group are most acidic. Hence they are removed by alkoxide preferably.
After removal of proton from aldehyde, a carbanion is generated. As it is a conjugated carbanion therefore the negative charge on carbon atom can conjugate through the carbonyl group to form an enolate which is another canonical form of the carbanion.
All the structures are shown below.
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Answer:
The true statements are:
The solution is acidic
The pH of the solution is 14.00 - 10.53.
Explanation:
The pH of the solution is defined as negative logarithm of hydrogen ion concentration present in the solution .
- The pH value more 7 means that hydrogen ion concentration is less ,alkaline will be the solution.
- The pH value less 7 means that hydrogen ion concentration is more ,acidic will be the solution.
- The pH value equal to 7 indicates that the solution is neutral.
The pOH of the solution is defined as negative logarithm of hydroxide ion concentration present in the solution .
The pOH of the solution = 10.53
The pH of the solution = ?
Here, the pH of the solution is less than 7 which means that solution acidic.