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sveta [45]
2 years ago
15

Amy performed an experiment in lab. She improperly mixed the chemicals, and an explosion of light, sound, and heat occurred. Whe

n Amy mixed the chemicals, energy was _______.
Chemistry
2 answers:
svlad2 [7]2 years ago
5 0

<span>The energy that was produced is called, heat combustion. It is an energy released in the form of heat when chemicals are mixed. An explosion of light and sound are the common characteristics of heat combustion. The chemical reaction takes place because of the presence of oxygen and hydrocarbon or organic molecule substances that when mixed form carbon dioxide and water which then releases heat and explosive characteristics.</span>

ElenaW [278]2 years ago
3 0

in other words the answer is transformed


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Here, the units of pressure and volume must be consistent and the temperature must be the absolute temperature (Kelvin or Rankine).
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Using the equation:
(755 x 500) / (27 + 273) = (494 x V) / (-33 + 273)
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What should be done if particles of precipitate appear in the filtrate?
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At a temperature of __________ °c, 0.444 mol of co gas occupies 11.8 l at 889 torr.
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The general term for a large molecule made up of many similar subunits is
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2 years ago
An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


3 0
2 years ago
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