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Nadusha1986 [10]
1 year ago
15

Tumu’s class was given an assignment to feature a scientist that contributed to the development of the cell theory. The class de

cided to use images to feature the scientist of their choice. Which image would Tumu most likely use in his assignment to feature Rudolf Virchow?
Chemistry
2 answers:
Agata [3.3K]1 year ago
6 0

Answer:

the way root cells reproduce to increase root length

Explanation:

Ad libitum [116K]1 year ago
4 0

Answer: the way root cells reproduce to increase root length

Explanation:

Rudolf Ludwig Carl Virchowas known as the founder of social medicine and also the father of modern pathology.

Virchow posited that all cells are gotten from already existing cells and he used this in his work towards cellular pathology, as it was made clear that diseases takes place at the cellular level. He posited that the cells that are malfunctioning cause diseases.

Based on the above analysis, the image that Tumu would most likely use in his assignment to feature Rudolf Virchow is the way root cells reproduce to increase root length.

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A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and
lianna [129]

Answer:

The correct option is: C. 250 K

Explanation:

Given: <em><u>Before Sublimation-</u></em>

Initial Temperature: T₁ = 300 K, Initial Pressure: P₁ = 1 atm, Initial number of moles of gas: n₁ = 1 mol, given mass of solid Carbon dioxide: w = 88 g    

<u><em>After Sublimation- </em></u>      

Final Pressure: P₂ = 2.5 atm, Final number of moles of gas: n₂ = ? mol

Final Temperature: T₂ = ? K,            

Also, Volume is constant, Molar mass of Carbon dioxide: m = 44 g/mol

As we know,

<em>The number of moles:</em>

n = \frac {given\: mass\: (w)} {Molar\: mass\: (m)}

<em>So the number of moles of carbon dioxide sublimed:</em>

n = \frac {w}{m} = \frac {88\: g} {44\: g/mol} = 2 mol

<em><u>Therefore, the final number of moles of gas after sublimation:</u></em>

n_{2} = n_{1} + n = 1\: mol + 2\: mol = 3\: mol

<u><em>According to the </em></u><u><em>Ideal gas equation</em></u><u><em>:</em></u>

P.V = n.R.T

or, \frac {P_{1}.V_{1}}{n_{1}.T_{1}} = \frac {P_{2}.V_{2}}{n_{2}.T_{2}} \: \: \: \: \: \: ....equation\: (1)

<em>Since the volume is constant, so the equation (1) can be written as:</em>

\frac {P_{1}}{n_{1}.T_{1}} = \frac {P_{2}}{n_{2}.T_{2}}

\Rightarrow \frac {1\:atm}{1\:mol \times 300\:K} = \frac {2.5\:atm}{3\:mol \times T_{2}}

\therefore T_{2} = \frac {2.5\:atm \times 300\:K \times 1\:mol}{3\:mol \times 1\:atm}

\Rightarrow T_{2} = 250\:K

<u>Therefore, the final temperature: T₂ = 250 K</u>

6 0
2 years ago
A 5.00 L sample of helium expands to 12.0 L at which point the
mina [271]

Answer:

1.73 atm

Explanation:

Given data:

Initial volume of helium = 5.00 L

Final volume of helium = 12.0 L

Final pressure = 0.720 atm

Initial pressure = ?

Solution:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

P₁ × 5.00 L = 0.720 atm × 12.0 L

P₁ = 8.64 atm. L/5 L

P₁ = 1.73 atm

7 0
1 year ago
A vessel contained N2, Ar, He, and Ne. The total pressure in the vessel was 987 torr. The partial pressures of nitrogen, argon,
xz_007 [3.2K]

Answer:

The partial pressure of neon in the vessel was 239 torr.

Explanation:

In all cases involving gas mixtures, the total gas pressure is related to the partial pressures, that is, the pressures of the individual gaseous components of the mixture. Put simply, the partial pressure of a gas is the pressure it exerts on a mixture of gases.

Dalton's law states that the total pressure of a mixture of gases is equal to the sum of the pressures that each gas would exert if it were alone. Then:

PT= P1 + P2 + P3 + P4…+ Pn

where n is the amount of gases present in the mixture.

In this case:

PT=PN₂ + PAr + PHe + PNe

where:

  • PT= 987 torr
  • PN₂= 44 torr
  • PAr= 486 torr
  • PHe= 218 torr
  • PNe= ?

Replacing:

987 torr= 44 torr + 486 torr + 218 torr + PNe

Solving:

987 torr= 748 torr + PNe

PNe= 987 torr - 748 torr

PNe= 239 torr

<u><em>The partial pressure of neon in the vessel was 239 torr.</em></u>

4 0
2 years ago
Methyl tertiary-butyl ether (MTBE) is an organic compound that has been in use since the late 1970s. Read the article to learn m
tamaranim1 [39]
H h I ointment o on NB j. Non b kkkk NB nis o ok kno kno
7 0
2 years ago
One of the buffers that contribute to pH stability in human blood is carbonic acid (H2CO3). Carbonic acid is a weak acid that, w
bonufazy [111]

Answer: the HCO3- to act as a base and remove excess H by the formation of H2CO3

Explanation:

H2CO3 in an aqueous solution is a buffer. This means the reaction is the following:

H2CO3 ------ HCO3- + H+

Then, the HCO3- that was formed acts as a base (absorbing a proton) like this

HCO3- + H+ ------- H2CO3

If there was an increase in H+, there would be an increase in the second reaction in an effort to neutralize that acid, thus making the H2CO3 more concentrated

7 0
2 years ago
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