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Nadusha1986 [10]
1 year ago
15

Tumu’s class was given an assignment to feature a scientist that contributed to the development of the cell theory. The class de

cided to use images to feature the scientist of their choice. Which image would Tumu most likely use in his assignment to feature Rudolf Virchow?
Chemistry
2 answers:
Agata [3.3K]1 year ago
6 0

Answer:

the way root cells reproduce to increase root length

Explanation:

Ad libitum [116K]1 year ago
4 0

Answer: the way root cells reproduce to increase root length

Explanation:

Rudolf Ludwig Carl Virchowas known as the founder of social medicine and also the father of modern pathology.

Virchow posited that all cells are gotten from already existing cells and he used this in his work towards cellular pathology, as it was made clear that diseases takes place at the cellular level. He posited that the cells that are malfunctioning cause diseases.

Based on the above analysis, the image that Tumu would most likely use in his assignment to feature Rudolf Virchow is the way root cells reproduce to increase root length.

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A sample of gas initially occupies 3.35 L at a pressure of 0.950 atm at 13.0oC. What will the volume (in L) be if the temperatur
Marat540 [252]

Answer: V= 3.13 L

Explanation: solution attached:

Use combine gas law equation:

P1 V1 / T1 = P2 V2/ T2

Derive to find V2

V2 = P1 V1 T2 / T1 P2

Convert temperatures in K

T1= 13.0°C + 273 = 286 K

T2= 22.5°C + 273 = 295.5 K

Substitute the values.

4 0
2 years ago
1. The specific heat capacity of iron is 0.461 J g–1 K–1 and that of titanium is 0.544 J g–1 K–1. A sample consisting of a mixtu
mezya [45]

Answer:

The answer is 80,1 °C

Explanation:

Let´s start from the mass of the sample and the heat capacities:

First of all, we must calculate an average heat capacity. That's because we have a mixture and it is unknown the heat capacity of the whole sample.

The way we should do this calculation is as follows:

(1) H_{average}=Mass Fraction_{first component}* H_{first component}+MassFraction_{secondcomponent}*H_{second component}

For example, the mass fraction of Fe is simply:

(2) MassFraction_{Fe}=\frac{10g Fe}{10g Fe + 10gTi}=0.5

If you combine the equations (1) and (2) you have:

(3) H_{average}=0.5*0.461+0.5*0.544=0.5025\frac{J}{g-K}

Once calculated the average heat capacity we can solve the problem taking into account the corresponding equation:

(4) Q=m*H_{average}*(T_2-T_1)

Remember that:

<em>Q:</em> Heat gained or lost

<em>m</em>: Mass of the sample you want to analize

H_{average} : The value obtained in equation (3)

T_2: Final temperature of the sample

T_1: Initial temperature of the sample

Now we must replace the problem data in equation (4)

Take into account:

  • Heat gained in a system have a positive value
  • Heat lost in a system have a negative value
  • In this problem the sample loses 200 J, for this reason Q=-200J
  • The mass of the whole sample is: 10g of Fe + 10g of Ti = 20g of sample
  • The temperatures must be in absolute units of temperature (these are: rankine or kelvin)
  • The initial temperature of the system is 100°C or 373K

Now we are ready to use equation (4):

(5) -200J=20g*0.5025\frac{J}{g*K} *(T_2-373K)

It is clear that the unknown in equation (5) is T_2

The next step is to calculate T_2. Don't forget the signs; these are important.

Key concept: <u>Since the system is loosing heat, the final temperature of the system ( T_2) should be lower than the initial temperature ( T_1 )</u>

7 0
2 years ago
Read 2 more answers
Looking at the same nonmetal group on the periodic table, how does the reactivity of an element in period 2 compare to the react
Bas_tet [7]

Answer : Option B) The period 2 element would be more reactive because the attractive force of protons is stronger when electrons are attracted to a closer electron shell.

Explanation : The reactivity of the Periods decreases as we go from left to right across a period. The farther to the left and down the periodic chart we go, the easier it is for electrons to be donated or taken away, resulting in higher reactivities of the elements. The attractive force of the protons is found to be stronger when electrons are found to be attracted to a closer electron shell.

4 0
1 year ago
Read 2 more answers
If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h
Kay [80]
At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
So Kc = [H2] [Br2] / [HBr]^2
7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root: 
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769 
7 0
2 years ago
Which quantity can vary among atoms of the same element?
Wewaii [24]
There is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number
7 0
1 year ago
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