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Stella [2.4K]
2 years ago
6

One of the buffers that contribute to pH stability in human blood is carbonic acid (H2CO3). Carbonic acid is a weak acid that, w

hen placed in an aqueous solution, dissociates into a bicarbonate ion (HCO3-) and a hydrogen ion (H ), as noted below. If the pH of blood drops, one would expect _____. One of the buffers that contribute to pH stability in human blood is carbonic acid (H2CO3). Carbonic acid is a weak acid that, when placed in an aqueous solution, dissociates into a bicarbonate ion (HCO3-) and a hydrogen ion (H ), as noted below. If the pH of blood drops, one would expect _____. the HCO3- to act as a base and remove excess H by the formation of H2CO3 the concentration of bicarbonate ions (HCO3-) to increase the HCO3- to act as an acid and remove excess H by the formation of H2CO3 a decrease in the concentration of H2CO3 and an increase in the concentration of HCO3-
Chemistry
1 answer:
bonufazy [111]2 years ago
7 0

Answer: the HCO3- to act as a base and remove excess H by the formation of H2CO3

Explanation:

H2CO3 in an aqueous solution is a buffer. This means the reaction is the following:

H2CO3 ------ HCO3- + H+

Then, the HCO3- that was formed acts as a base (absorbing a proton) like this

HCO3- + H+ ------- H2CO3

If there was an increase in H+, there would be an increase in the second reaction in an effort to neutralize that acid, thus making the H2CO3 more concentrated

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kap26 [50]
Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
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Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

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When we put it together: our complete stoichiometry problem would look like this:

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Hope I could help!
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