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poizon [28]
2 years ago
12

Question 6 if a gas pressure gauge reads 32.0 psi, what is the pressure in inches of mercury? 165 in. hg 15.7 in. hg 65.1 in. hg

32.0 in. hg 6.19 in. hg
Chemistry
1 answer:
MA_775_DIABLO [31]2 years ago
5 0
Psi and in.Hg are both units used to measure pressure. 
psi stands for pounds per square inch and in.Hg stands for inches in mercury.
1 psi is equivalent to 2.036 in.Hg
therefore 32.0 psi is equivalent to 2.036 in.Hg /psi x 32.0 psi = 65.1 in.Hg
therefore answer is 65.1 in. Hg
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Three mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,
8_murik_8 [283]

Answer:

(a). 46,666.7 g/mol; 78,571.4 g/mol

(b). 86950g/mol; 46,666.7 g/mol.

(c). 86950g/mol; 43,333.33 g/mol

Explanation:

So, we are given the molar masses for the three samples as: 10,000, 30,000 and 100,000 g mol−1.

Thus, the equal number of molecule in each sample = ( 10,000 + 30,000 + 100,000 ) / 3 = 46,666.7 g/mol.

The average molar mass = [ ( 10,000)^2 + (30,000)^2 + 100,000)^2] ÷ 10,000 + 30,000 + 100,000 = 78,571. 4 g/mol.

(b). The equal masses of each sample = 3/[ ( 1/ 10,000) + (1/30,000 ) + (1/100,000) ] = 20930.23 g/mol.

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(c). Equal masses of the two samples = (0.145 × 10,000) + (0.855 × 100,000)/ 0.145 + 0.855 = 86950g/mol.

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6 0
1 year ago
What mass (g) of barium iodide is contained in 188 ml of a barium iodide solution that has an iodide ion concentration of 0.532m
Katarina [22]

Answer:

What mass (g) of barium iodide is contained in 188 mL of a barium iodide solution that has an iodide ion concentration of 0.532 M?

A) 19.6

B) 39.1

C) 19,600

D) 39,100

E) 276

The correct answer to the question is

B) 39.1  grams

Explanation:

To solve the question

The molarity ratio is given by

188 ml of 0.532 M solution of iodide.

Therefore we have number of moles = 0.188 × 0.532 M = 0.100016 Moles

To find the mass, we note that the Number of moles = \frac{Mass}{Molar Mass} from which we have

Mass = Number of moles × molar mass

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= 0.100016 moles ×391.136 g/mol = 39.12 g

8 0
1 year ago
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elena-s [515]

Hello user, you did not add a picture of an attachment to enable me help you solve this problem. Please check the attachment I added i believe it is the question that needs to be solved.

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b. Add water to pure drink mix solution

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a. Add pure drink mix solution to pure drink mix solution

b. Drain the pure drink mix solution

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7 0
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