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poizon [28]
2 years ago
12

Question 6 if a gas pressure gauge reads 32.0 psi, what is the pressure in inches of mercury? 165 in. hg 15.7 in. hg 65.1 in. hg

32.0 in. hg 6.19 in. hg
Chemistry
1 answer:
MA_775_DIABLO [31]2 years ago
5 0
Psi and in.Hg are both units used to measure pressure. 
psi stands for pounds per square inch and in.Hg stands for inches in mercury.
1 psi is equivalent to 2.036 in.Hg
therefore 32.0 psi is equivalent to 2.036 in.Hg /psi x 32.0 psi = 65.1 in.Hg
therefore answer is 65.1 in. Hg
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mojhsa [17]

Answer:

The change in color.

Explanation:

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3 0
2 years ago
identify A and B, isomers of molecular formula C3H4Cl2, from the given 1H NMR data: Compound A exhibits peaks at 1.75 (doublet,
siniylev [52]

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

3 0
2 years ago
At 10 K Cp,m(Hg(s)) = 4.64 J K−1 mol−1. Between 10 K and the melting point of Hg(s), 234.3 K, heat capacity measurements indicat
umka21 [38]

Answer:

S°m,298K = 85.184 J/Kmol

Explanation:

∴ T = 10 K ⇒ Cp,m(Hg(s)) = 4.64 J/Kmol

∴ 10 K to 234.3 K ⇒ ΔS = 57.74 J/Kmol

∴ T = 234.3 K ⇒ ΔHf = 2322 J/mol

∴ 234.3 K to 298.0 K ⇒ ΔS = 6.85 J/Kmol

⇒ S°m,298K = S°m,0K + ∫CpdT/T(10K) + ΔS(10-234.3) + ΔHf/T(234.3K) + ΔS(234.3-298)

⇒ S°m,298K = 0 + 10.684 J/Kmol + 57.74 J/Kmol + 9.9104 J/Kmol + 6.85 J/kmol

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4 0
2 years ago
How many liters of a 0.0550 M NaF solution contain 0.163 moles of NaF?
Kobotan [32]

Answer : The volume of solution will be 2.96 liters.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

In this question, the solute is NaF.

Now put all the given values in this formula, we get:

0.0550M=\frac{0.163mole}{\text{Volume of solution (in L)}}

\text{Volume of solution (in L)}=\frac{0.163mole}{0.0550M}

\text{Volume of solution (in L)}=2.96L

Therefore, the volume of solution will be 2.96 liters.

3 0
2 years ago
If a large marshmallow has a volume of 2.50 i n 3 and density of 0.242 g/c m 3 , how much would it weigh in grams? 1 i n 3 =16.3
Illusion [34]

Density of a substance is defined as the mass of the substance divided by the volume.

Density of the substance= 0.242 g cm⁻³  

volume of the substance= 2.50 in³  

As, 1 in³= 16.39 cm³  

So, 2.50 in³= 16.39× 2.50 cm³=40.97 cm³

As ,  

Density=\frac{mass}{volume}  

Mass=volume ×Density

Mass=40.97 × 0.242

Mass=9.916 g.

4 0
2 years ago
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