Answer:
The answer to your question is P = 1.357 atm
Explanation:
Data
Volume = 22.4 L
1 mol
temperature = 100°C
a = 0.211 L² atm
b = 0.0171 L/mol
R = 0.082 atmL/mol°K
Convert temperature to °K
Temperature = 100 + 273
= 373°K
Formula
Substitution
Simplify
(P + 0.0094)(22.3829) = 30.586
Solve for P
P + 0.0094 =
P + 0.0094 = 1.366
P = 1.336 - 0.0094
P = 1.357 atm
Answer: The average atomic mass of the element X is 51.99592 amu
Explanation:
Mass of isotope 1 = 49.94605 amu
% abundance of isotope 1 = 4.350% =
Mass of isotope 2 = 51.94051 amu.
% abundance of isotope 2 = 83.79% =
Mass of isotope 3 = 52.94065 amu.
% abundance of isotope 2 = 9.500% =
Mass of isotope 4 = 53.93888 amu.
% abundance of isotope 2 = 2.360% =
Formula used for average atomic mass of an element :
Therefore, the average atomic mass of the element X is 51.99592 amu
Answer:
B = CHCl2 + Cl2 --> CHCl3 + Cl
Explanation:
Free radical halogenation is a chlorination reaction on Alkane hydrocarbons. This involves the splitting of molecules into radicals/ unstable molecules in the presence of sunlight/ U.V light which ensures bonding of the molecules.
Free radical chlorination is divided into 3 steps which are:
The initiation step
The propagation step
The termination step
So in reference to the question, propagation step involves two steps.
The first step is where the molecule in this case the methylene chloride(CH2Cl2) loses a hydrogen atom and then bond with a chlorine atom radical to give a nethylwnw chloride radical and HCl.
The second step involves the reaction of this methylene chloride got in the first step with chlorine molecule to form trichloride methane and a chlorine radical.
You would find in the attachment the 2 step mechanism.
