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SashulF [63]
2 years ago
15

The requirements for one type of atom to substitute for another in a solid solution are:

Chemistry
1 answer:
Zinaida [17]2 years ago
5 0

Answer: Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.

Answer:

Explanation: Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.

Answer:

Pine trees, straw Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.

Answer:

erry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate the Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.

Answer:

se members of the Plantae kingdom into smaller groups.

Answer:

Pine trees, strawberry plants, and cacti are all plants. Name and describe three or more characteristics that you think scientists could use to separate these members of the Plantae kingdom into smaller groups.

Answer:

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These images of the Santa Cruz River in Arizona were taken in 1942 and 1989. During the period between these years, the growth o
icang [17]

The roots could no longer access depleted groundwater.


The topsoil in the area eroded.



7 0
2 years ago
When a known quantity of compound, at a known concentration, is added to a known volume of another compound to determine the con
Vladimir [108]

Answer:

A titration

Explanation:

A common example of a titration is when we have an acid of unknown concentration, so we add a known volume of a base of known concentration. This process lets us determine the concentration of the acid.

By definition, a titration is a quantitative analysis, as we determine how much of an analyte is there in a sample. However, <u>there are quantitative analyzes which are not titrations</u>. This is why the most appropiate answer is<em> a titration</em>.

5 0
2 years ago
Determine the compound type for the following formulas: C12H22011 Mg(OH)2 H20 Cu3Zn2 Au <br>​
Scorpion4ik [409]

Answer:

C12H22O11  

✔ covalent

Mg(OH)2    

✔ Ionic

H2O    

✔ covalent

Cu3Zn2    

✔ metallic

Au      

✔ metallic

Explanation:

7 0
2 years ago
Read 2 more answers
What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B
gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine (c), measured in moles per cubic decimeter, can be determined by the following formula:

c = \frac{m}{M\cdot V} (1)

Where:

m - Mass of iodine, measured in grams.

M - Molar mass of iodine, measured in grams per mol.

V - Volume of solution, measured in cubic decimeters.

If we know that m = 2.54\,g, M = 253.809\,\frac{g}{mol} and V = 0.25\,dm^{3}, then the concentration of iodine in a solution is:

c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}

c = 0.04\,\frac{mol}{dm^{3}}

Hence, the correct answer is C.

3 0
2 years ago
How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
2 years ago
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