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ale4655 [162]
1 year ago
13

A tank holds 6.90 m3 of water. What is the volume in ft3? (3.28 ft = 1 m, Remember significant figures, but this answer does not

need units, since the answer must be in ft3)
Chemistry
1 answer:
AleksAgata [21]1 year ago
5 1

Volume of tank = 6.9 m^{3} (given)

Since, 1 m = 3.28 ft

So,  

1 m^{3} = 35.287 ft^{3}

For 6.9 m^{3}:

6.9\times 35.287 ft^{3} = 243.4803 ft^{3}

The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

243.4803 ft^{3} \simeq 243.5 ft^{3}

Hence, volume in ft^{3} is 243.5.

You might be interested in
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
1 year ago
36g of KOH dissolved in 800mL of water. What is the molality of the solution?
Bad White [126]

Answer:

0.80m of KOH

Explanation:

Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, the solute is KOH and solvent is water.

Moles of 36g KOH -Molar mass: 56.1g/mol- are:

36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>

<em></em>

Now, as density of water is 1g/mL, mass of 800mL of water is:

800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>

<em></em>

Thus, molality is:

0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>

5 0
2 years ago
Americium-242 has a half-life of 6 hours. If you started with 24 g and you now have 3 g, how much time
kogti [31]
How many times has it halved?

24/2 = 12
12/2 = 6
6/2 = 3

It halved three times.
It halves once every 6 hours.

18 hours have passed.
7 0
2 years ago
What is the volume, in liters, occupied by 1.73 moles of N2 gas at 0.992 atm pressure and a temperature of 75º C? (R value- 0.08
taurus [48]

Volume of the nitrogen gas = 49.8 L

<u>Explanation:</u>

It is given that the pressure, number of moles and temperature of nitrogen gas, and gas constant value being constant and it is taken as 0.08206 L atm mol⁻¹K⁻¹.

Temperature = T = 75°C = 75 + 273 = 348 K

Pressure = P = 0.992 atm

Number of moles = n = 1.73 moles

We have to use the ideal gas equation, PV = nRT, and rearranging the equation to get Volume in litres.

V = $\frac{nRT}{P}

 = $\frac{1.73\times 0.08206\times348}{0.992}

= 49.8 L

So the volume of Nitrogen gas = 49.8 L

7 0
1 year ago
What molecule is the ultimate source of hydrogen ions that are secreted into the gastric juice?
sladkih [1.3K]

Answer: carbonic acid

Explanation:

8 0
2 years ago
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