Answer:
D
Explanation:
I - You should account the mass of the weighing paper to reduce it from the total mass at the end of the process, having only the mass of the Silver Chloride.
II - The precipitation of the silve chloride will occur independently of the temperature, because the Kps of this salt is very low (Ksp = [Ag+] .[Cl-]).
III - Washing the precipitate will secure the purity of the final product, it won't allow any other contaminant to be in your precipitante which could change your final mass.
IV - You should heat you AgCl precipitate so it will be dry, because of that the mass you will obtain is only the mass of the weighing paper and the silver chloride and nothing else.
Answer:
"statement 2" for the first pair and "statement 1" for the second pair
Explanation:
The correct reaction equation is:

Answer:
b) 1 mole of water is produced for every mole of carbon dioxide produced.
Explanation: <u>CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.</u>
a) <u>22.4 L of
gas</u> is produced only when <u>
L of
</u> is reacted with 22.4 L of
. So it is wrong.
b) Since in the chemical equation the stoichiometric coefficient of
and
are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. <u>Therefore it is correct option.</u>
c)
molecules is equal 1 mole of
if produced then 3 moles of
is required, which is not given in the option. So it is wrong.
d) 54 g of water or 3 moles of
(<em>Molecular Weight of water is 18 g</em>) is produced when 3 moles of
is used but in this option only one mole of
is given. So it is wrong.
The answer to this question would be: 3.125%
Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
S, sulfur does not have a noble gas electron.