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Ronch [10]
2 years ago
11

Mendeleev placed thallium (Tl) in the same group as lithium (Li), sodium (Na), potassium (K), rubidium (Rb), and cesium (Cs). Ho

wever, the modern periodic table doesn’t place thallium in this group. Use the periodic table to find the properties of thallium. Explain why Mendeleev might have grouped thallium in the same group as lithium and sodium. Also explain how thallium is different from the other five elements.
Chemistry
1 answer:
IceJOKER [234]2 years ago
4 0

Answer:

Mendeleev placed thallium (Tl) in the same group as lithium (Li), sodium (Na), potassium (K), rubidium (Rb), and cesium (Cs)

Explanation:

Properties of Thallium :

Thallium is a heavy metal denoted by symbol Tl. It is placed in 13th group and 6th period of modern periodic table. It is very soft in nature. It has 3 valency. It does not occur freely in environment.

Mendeleev  grouped thallium in the same group as lithium and sodium because of he found that as Li, Na etc. have compound with one atom of chlorine(Cl), Thallium(Tl) also forms TlCl. Therefore he placed Tl with these elements.

Thallium is different from the other five elements

Tl has 3 valency whereas lithium (Li), sodium (Na), potassium (K), rubidium (Rb), and cesium (Cs) has only 1 valency.

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Veseljchak [2.6K]

Answer:

Explanation:

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4 0
2 years ago
The standard reduction potentials for two half-cells involving iron are: given below. Fe2+ (aq) + 2e– ® Fe (s) Eο = –0.44 V Fe3+
matrenka [14]

Answer:

Explanation:

Fe⁺² (aq) + 2e⁻ =   Fe (s)   ;   E⁰ =  - .44 V

Fe⁺³ (aq) + e⁻ =  ® Fe²⁺ (aq) ;   E⁰ = + .77 V

Reduction potential of second reaction is more , so it will take place , ie Fe⁺³ will be reduced and Fe will be oxidised .

So reaction in the combined cell will be

2Fe⁺³ + Fe = 3Fe⁺²

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6 0
2 years ago
HA and HB are two strong monobasic acids. 25.0cm3 of 6.0mol/dm3 HA is mixed with 45.0cm3 of 3.0mol/dm3 HB.
Lostsunrise [7]

Answer:

The H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

(Option C)

Explanation:

Given;

concentration of HA, C_A = 6.0mol/dm³

volume of HA, V_A  = 25.0cm³, = 0.025dm³

Concentration of HB, C_B = 3.0mol/dm³

volume of HB, V_B = 45.0cm³ = 0.045dm³

To determine the H+ (aq) concentration in mol/dm³ in the resulting solution, we apply concentration formula;

C_iVi = C_fV_f

where;

C_i is initial concentration

V_i is initial volume

C_f is final concentration of the solution

V_f is final volume of the solution

C_iV_i = C_fV_f\\\\Based \ on \ this\ question, we \ can \ apply\ the \ formula\ as;\\\\C_A_iV_A_i + C_B_iV_B_i = C_fV_f\\\\C_A_iV_A_i + C_B_iV_B_i = C_f(V_A_i\ +V_B_i)\\\\6*0.025 \ + 3*0.045 = C_f(0.025 + 0.045)\\\\0.285 = C_f(0.07)\\\\C_f = \frac{0.285}{0.07} = 4.07 = 4.1 \ mol/dm^3

Therefore, the H+ (aq) concentration of the resulting solution is 4.1 mol/dm³

7 0
2 years ago
A bag of fertilizer is labeled 10-20-20. What is the actual percentage of phosphorus in the fertilizer?
aleksandr82 [10.1K]

Answer:

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Explanation:

A fertilizer is used to improve the fertility of soils. Most fertilizers contains the element nitrogen, phosphorus and potassium.

They are often designated NPK fertilizers.

  Now we know that the numbers 10-20-20 depicts the nitrogen-phosphorus and potassium content of the fertilizer.

From the designation,

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8 0
2 years ago
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mars1129 [50]

Answer:

59.2 grams

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There are 59.2 grams of water in this solution.

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2 years ago
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