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tangare [24]
2 years ago
9

How many moles of O2 would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 73.3% yi

eld? 2 NO (g) + O₂ (g) → 2 NO2 (g)
What mass of aspirin (C₉H₈O₄) is produced from 52.1 g of C₇H₆O₃ assuming 95.0% yield from the reaction below? C₇H₆O₃ (s) + C₄H₆O₃ (s) → C₉H₈O₄ (s) + HC₂H₃O₂ (aq).
In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 62.16 g of MgI₂ form, what is the percent yield?
The synthesis of maleic acid anhydride (C₄H₂O₃) can be accomplished by reacting benzene (C₆H₆) and oxygen gas in the following chemical reaction:
2 C₆H₆(l) + 9 O₂(g) → 2 C₄H₂O₃(s) + 4 CO₂(g) + 4 H₂O(g)


If 8.00 moles of NH₃ of and 10.00 moles of O₂ react in the following reaction, how many moles of which reactant will be left over?
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
If 0.275 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ could be formed?
AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + HNO₃ (aq)
If 37.3 g of NO and 26.9 g of O₂ react together, how many grams of NO₂ can be formed via the reaction below?
2 NO (g) + O₂ (g) → 2 NO₂ (g)
You have 2.2 mol Xe and 3.8 mol F₂, but when you carry out the reaction you end up with only 0.25 mol XeF₄. What is the percent yield of this experiment? Xe(g) + 2 F₂ (g) → XeF₄ (g)
Chemistry
1 answer:
Airida [17]2 years ago
4 0

Answer:

Mmmmmmmmmmmmmmm

Explanation:

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Joyce poured 200 milliliters (mL) of water into a beaker, placed a thermometer in it, and heated it until it started to boil. Sh
earnstyle [38]

Answer:

100°C

Explanation:

The boiling point of water is 100°C and the difference is when will the water start boiling.

3 0
2 years ago
In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 27.0 ∘C . You identified that the ideal pressure
dimaraw [331]

Answer : The percent difference between the ideal and real gas is, 4.06 %.

Explanation : Given,

Ideal pressure (true value) = 49.3 atm

Real pressure (measured value) = 47.3 atm

The formula used to calculate percent difference is :

Percent difference = \frac{\text{True value - Measured value}}{\text{True value}} \times 100

Percent difference = \frac{(49.3- 47.3)atm}{49.3atm}\times 100

Percent difference = 4.06 %

Therefore, the percent difference between the ideal and real gas is, 4.06 %.

4 0
2 years ago
Calculate the molarity of 1.0 mol of KCl in 750 ml of solution
Vaselesa [24]

Answer:

[KCl] = 1.33 M

Explanation:

Molarity is mol /L

Mol of solute in 1 L of solution

Volume of solution is 750 mL

750 mL / 1000 = 0.750 L

1 mol / 0.750L = M → 1.33

7 0
2 years ago
Read 2 more answers
A solution contains cr3+ ions. the addition of 0.063 l of 1.50 m naf solution was needed to completely precipitate the chromium
steposvetlana [31]

Cr{3+} + 3 NaF → CrF3 + 3 Na{+} <span>

First calculate the total mols of NaF. 

(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>

 

Using stoichiometric ratio:

<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) = 1.6379 g Cr3+</span>
6 0
2 years ago
n the diagram shown, when an object ‘X’ is brought near the ring shaped magnet, the magnet moves away from it. Four friends are
kati45 [8]

Answer:

Akash

Explanation:

it could be a magnet with the same poles facing eachoher

6 0
2 years ago
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