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LekaFEV [45]
2 years ago
15

Which equation illustrates conservation of mass?

Chemistry
2 answers:
Flauer [41]2 years ago
7 0

Answer:

None as written.

Explanation:

Unless 2 meant H2 + Cl2  = 2HCl

pochemuha2 years ago
4 0
Answer = c


Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.
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X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc
Cerrena [4.2K]

Explanation:

Given: \lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}

Its frequency \nu is defined as

\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}

\:\:\:\:= 3.58×10^{16}\:\text{Hz}

7 0
1 year ago
A sample of a solid labeled as NaCl may be impure. a student analyzes the sample and determines that it contains 75 percent chlo
Evgesh-ka [11]

Answer:

D

Explanation:

The sample must contain impurity that is lower in atomic mass to sodium and since potassium has higher atomic mass to sodium, the answer is the sample contains NaCl and LiCl. We are sure already that the sample is not pure which rules out  option a and option b contains sodium iodide which cannot contribute to the increase in chlorine

5 0
2 years ago
What elements of paint can help forensic scientists compare samples to each other?
saul85 [17]
It would have to be paints consists of pigments,solvents, and binders. Once the [paint has been applied and has dried, the pigments are still able to determine the matched samples.
4 0
2 years ago
What is the maximum volume of a 0.788 M CaCl2 solution that can be prepared using 85.3 g CaCl2
LekaFEV [45]
Molar mass CaCl₂ = 111.0 g/mol

number of moles:

n = mass of solute / molar mass

n = 85.3 / 111.0

n = 0.7684 moles of CaCl₂

M = n / V

0.788 M = <span>0.7684 / V
</span>
V = 0.7684 / 0.788

V = 0.97512 L

hope this helps!


3 0
2 years ago
The volume of a gas is 36.0 ml at 10.0°c and 4.50 atm. at what temperature (°c) will the gas have a pressure of 3.50 atm and a v
galben [10]
Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
5 0
2 years ago
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