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1 year ago

Which equation illustrates conservation of mass?

Chemistry

2 answers:

Flauer [41]1 year ago

7 0

Answer:

None as written.

Explanation:

Unless 2 meant H2 + Cl2 = 2HCl

pochemuha1 year ago

4 0

Answer = c

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.

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A 3.81-gram sample of NaHCO3 was completely decomposed in an experiment. 2NaHCO3 → Na2CO3 + H2CO3 In this experiment, carbon dio

Oksanka [162]

Answer:

The percent yield of H_2CO_3 is, 24.44 %

Explanation:

5 0

2 years ago

A 0.72-mol sample of PCl5 is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl3(g) and 0.

Sonja [21]

Answer:

Equilibrium constant for $PCl_5$ is 0.5

Equilibrium constant for decomposition of $NO_2$ is $1.79 \times 10^{-14}$

Explanation:

$PCl_5$ dissociates as follows:

$PCl_5 \rightleftharpoons PCl_3+Cl_2$

initial 0.72 mol 0 0

at eq. 0.72 - 0.40 0.40 0.40

Expression for the equilibrium constant is as follows:

$k=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

Substitute the values in the above formula to calculate equilibrium constant as follows:

$k=\frac{[0.40/1][0.40/1]}{0.32/1} \\=\frac{0.40 \times 0.40}{0.32} \\=0.5$

Therefore, equilibrium constant for $PCl_5$ is 0.5

Now calculate the equilibrium constant for decomposition of $NO_2$

It is given that $3.3 \times 10^{-3} \%$ is decomposed.

$NO_2$ decomposes as follows:

$2NO_2 \rightleftharpoons 2NO + O_2$

initial 1.0 M 0 0

at eq. concentration of $NO_2$ is:

$[NO_2]_{eq}=1-(0.000066) = 0.999934\ M$

$[NO]_{eq}=6.6 \times 10^{-5}\ M$

$[O_2]_{eq}=3.3\times 10^{-5} = 3.3\times 10^{-5}\ M$

Expression for equilibrium constant is as follows:

$K=\frac{[NO]^2[O_2]}{[NO_2]^2}$

Substitute the values in the above expression

$K=\frac{[6.6\times 10^{-5}]^2[3.3 \times 10^{-5}]}{[0.999934]^2} \\=1.79\times 10^{-14}$

Equilibrium constant for decomposition of $NO_2$ is $1.79 \times 10^{-14}$

8 0

2 years ago

Empirical formula for H2S2O8

NeX [460]

<span>What is the molecular formula of a compound containing 25.6g of oxygen, 12.6g of sulfur and 0.4g of hydrogen? The Mr of the compound is 194.2</span>

4 0

1 year ago

a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0

bixtya [17]

Answer:

T₂ = 669.2 K

Explanation:

Given data:

Initial pressure = 660 torr

Initial temperature = 26 °C (26 +273 = 299 K)

Final volume = 280 mL ( 280/1000 = 0.28 L)

Final pressure = 940.0 torr

Final volume = 0.44 L

Final temperature = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂ T₁ /P₁V₁

T₂ = 940 torr × 0.44 L × 299 K / 660 torr × 0.28 L

T₂ = 123666. 4 torr. L. K / 184.8 torr. L

T₂ = 669.2 K

3 0

1 year ago

The standard hydrogen electrode:

tiny-mole [99]

Answer:

is a simple, safe, and easy-to-create electrode

Explanation:

the hydrogen electrode is based on the redox half-cell:

2H+(aq) + 2e- → H2(g)

building:

1) Platinium electrode

2) hydrogen pumping

3) acid solution [H+] = 1M

4) siphon to prevent oxygen presence

5) galvanic cell connector

this electrode is used as the basis for standard potential tables

3 0

2 years ago