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2 years ago

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

1 answer:

6 0

$C_{m}=\frac{m}{MV}=\frac{73,5g}{98\frac{g}{mol}*3L}=0,25M\\\\
C_{1}V_{1}=C_{2}V_{2}\\\\
0,25M*3L=0,18M*V_{2}\\\\
V_{2}=\frac{0,25M*3L}{0,18M}\approx 4,17L\\\\
4,17L-3L=1,17L$

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How many g i2 should be added to 750g ccl4 to prepare a 0.200m solution?

vesna_86 [32]

There are a number of ways to express concentration of a solution. This includes molality. Molality is expressed as the number of moles of solute per mass of the solvent. We calculate as follows:

0.200 mol I2 / kg CCl4 ( .750 kg CCl4 ) ( 253.809 g I2 / mol I2) = 38.07 g I2 needed

Hope this helps.

6 0

2 years ago

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What should be done if particles of precipitate appear in the filtrate?

Volgvan

The instructor should be questioned to see if the filtrate is able to be recycled. This precipitate can contaminate the filtrate, rendering it useless for repeated experiments. If it is able to be recycled, a second pass through the filter might be required to remove the precipitate.

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2 years ago

Determine the poh of a 0.348 m ba(oh)2 solution at 25°c.

vladimir1956 [14]

Given:

Concentration of Ba(OH)2 = 0.348 M

To determine:

pOH of the above solution

Explanation:

Based on the stoichiometry-

1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion

Therefore, concentration of OH- ion = 2*0.348 = 0.696 M

pOH = -log[OH-] = - log[0.696] = 0.157

Ans: pOH of 0.348M Ba(OH)2 is 0.157

6 0

2 years ago

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On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of

joja [24]

Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

$C\propto P$

$C=K_H\times P$

$K_H$ is Henry's constant.

or,

$\frac{C_1}{C_2}=\frac{P_1}{P_2}$

where,

$C_1$ = initial concentration of gas = $5.3\times 10^{-4}M$

$C_2$ = final concentration of gas = $2.0\times 10^{-3}M$

$P_1$ = initial partial pressure of gas = 0.78 atm

$P_2$ = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

$\frac{5.3\times 10^{-4}M}{2.0\times 10^{-3}M}=\frac{0.78atm}{P_2}$

$P_2=2.94atm$

Therefore, the partial pressure of nitrogen gas is, 2.94 atm

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2 years ago

Match the following names of glassware with what you would use them for.(1) Glassware used to accurately transfer small volumes.

Andrei [34K]

Answer:

(1)=(A), (2)=(B), (3)=D, (4)=C, (5)=E, (6)=F

Explanation:

(1) Glassware used to accurately transfer small volumes = (A) Graduated pipette, that is basically a glass tube with graduation of different volumes to be dispensed.

(2) Glassware used to accurately transfer a small, single volume = (B) Volumetric pipette, that is a glass tube with a central glass bulb and is used to dispense accurately an unique volume of liquid everytime.

(3) Glassware to deliver a volume not known in advance = (D) Buret (or burette), that is used to dispense slowly a volume of liquid when a titration process is needed

(4) Glassware best used when greater access to the contents is needed = (C) Beaker, that is basically a very open glass cylinder with a spout

(5) Glassware used to prevent splashing or evaporation = (E) Erlenmeyer flask, that has a small open at the top and is useful when the liquid needs to be swirled as, for example, during a titration.

(6) Glassware used to make accurate solutions = (F) Volumetric flask, that has a long slim neck that provides a higher accuracy when a exact volume of liquid needs to be used for preparation of a solution.

8 0

2 years ago