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Whitepunk [10]
1 year ago
8

The following do not represent valid ground-state electron configurations for an atom either because they violate the Pauli excl

usion principle or because orbitals are not filled in order of increasing energy. Indicate which of these two principles is violated in each example or whether both or neither are violated.
Part 1
1s22s23s2
A) The orbitals are not filled in order of increasing energy.
B) The Pauli exclusion principle is violated.
C) Orbitals are not filled in order of increasing energy and the Pauli exclusion principle is violated.
D) The ground-state electron configuration is valid.
Part 2
[Rn]7s26d4
A) The orbitals are not filled in order of increasing energy.
B) The Pauli exclusion principle is violated.
C) Orbitals are not filled in order of increasing energy and the Pauli exclusion principle is violated.
D) The ground-state electron configuration is valid.
Part 3
[Ne]3s23d5
A) The orbitals are not filled in order of increasing energy.
B) The Pauli exclusion principle is violated.
C) Orbitals are not filled in order of increasing energy and the Pauli exclusion principle is violated.
D) The ground-state electron configuration is valid.
Chemistry
2 answers:
svetoff [14.1K]1 year ago
7 0

Answer:

<em>For both cases the answer is C</em>

Explanation:  

We can see that the orbitals are not filled in the order of increasing energy and the Pauli exclusion principle is violated because it does not follow the correct order of the electron configuration; In the first exercise after the 2s2 orbital, the 2p2 orbital follows.

For the second exercise, you must start in order with level 1 and correctly filling each of the sublevels corresponding to each level until reaching level 7 and thus completing the desired number of electrons.

Kipish [7]1 year ago
7 0

Answer:

for both parts the ans is c

hope helps you

have a great day

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How does the arrangement of atoms in a mineral relate to its properties?
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The arrangement of atoms in a mineral can change its physical and chemical properties. 
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The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this
dimaraw [331]

Answer:

C₄F₈

Explanation:

Using their mole ratio to compute their mass

molar mass of carbon = 12.0107 g/mol

molar mass of fluorine gas = 37.99681

let x = mass of carbon

given mass of fluorine = 1.70 g

x / 12.01067 = 1.70 / 37.99687

cross multiply

x = ( 1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g

mass of one mole of CF₂ = 0.53688 + 1.70 = 2.23688 g

number of mole of CF₂ = 8.93 g / 2.23688 = 3.992 approx 4

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3 0
2 years ago
4. Convert the following: a. 4g mol of MgCl2 to g b. 2 lb mol of C3H8 to g c. 16 g of N2 to lb mol d. 3 lb of C2H6O to g mol
Nuetrik [128]

Answer:

a) 381.2 g

b) 39916 g

c) 0.0013 lb mol

d) 29.6 g mol

Explanation:

The molecular weight (mw) of a compound is the mass of it per mole, so it's the ratio of the mass (m) per mole (n).

a) The molecular weight of one mol is found at the periodic table. So, for Mg, mw = 24.3 g/mol, for Cl = 35.5 g/mol, so for MgCl2, mw = 24.3 + 2*35.5 = 95.3 g/mol. The g mol is the mass divided by the molecular weight:

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4 = m/95.3

m = 381.2 g

b) The pound (lb) is a unity of mass, and the lb mol is a unity of the mass divided by the molecular weight. So, by the periodic table, the molecular weight of C3H8 is 3*12 (of C) + 8*1 (of H) = 44 lb/mol.

lb mol = m/mw

2 = m/44

m = 88 lb

1 lb = 453.592 g

So, m = 88*453.592 = 39916 g

c) The molecular weight of N2 is 2*14 (of N) = 28 lb/mol.

m = 16/453.592 = 0.0353 lb

lb mol = m/mw

lb mol = 0.0353/28

lb mol = 0.0013 lb mol

d) The molecular weight is 2*12 (of C) + 6*1(of H) + 1*16(of O) = 46 g/mol

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g mol = 1360.78/46

g mol = 29.6 g mol

6 0
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Hey there!:

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Answer:

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