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cestrela7 [59]
2 years ago
14

A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?

Chemistry
2 answers:
MatroZZZ [7]2 years ago
8 0
Letter d, because they are both alkali metals (group one)
Mama L [17]2 years ago
7 0

Answer: D

Explanation: because i had to same question & got it right

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If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products
puteri [66]

<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

4 0
2 years ago
A piece of silver releases 202.8 J of heat while cooling 65.0 °C. What is the mass of the sample? Silver has a specific heat of
KiRa [710]

Answer: 13 grams

Explanation:

The quantity of heat energy (Q) released from a heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 202.8 Joules

Mass of silver = ?

C = 0.240 J/g °C.

Φ = 65°C

Then, Q = MCΦ

202.8J = M x 0.240 J/g °C x 65°C

202.8J = M x 15.6 J/g

M = (202.8J / 15.6 J/g)

M = 13 g

Thus, the mass of silver is 13 grams

7 0
2 years ago
What does the number represent in the isotope platinum-194?
vazorg [7]
The number in isotope platinum-194 stands for the <em>total </em>amount of protons and neutrons. In other words, this is the mass. =)
4 0
2 years ago
The diagram below shows the different phase transitions that occur in matter. Three bars are shown labeled Solid, Liquid, and Ga
Sergio [31]

Answer:

Molecules are speeding up as boiling occurs.

Explanation:

We have three states of matter;solid liquid and gas. Substances are found in these different states of matter according to the degree of energy and velocity of its particles. Highly energetic particles moving at high velocities are found in the gaseous state. Less energetic particles moving at lesser velocities due to intermolecular forces are found in the liquid state while particles with the least degree of freedom are found in the solid state. Solid particles do not translate but can vibrate or rotate about a fixed position.

When a liquid boils, particles at the surface of the liquid acquire sufficient energy and escape the surface of the liquid. This is because, as energy is supplied in the form of heat during boiling, molecules acquire sufficient energy to speed up their molecular motion and escape the liquid surface as vapour.

6 0
2 years ago
Read 2 more answers
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
2 years ago
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