An example.
water is H2O
2 hydrogen, 1 oxygen
so the number to the right means how much of what is on the left.
so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)
so 6 carbons, 12 hydrogen
the ratio of c2 to h4 doesn't change it's always 1:2.
but the 3 at the front is a different number relating to how much you have
Answer: Reaction 1 is non spontaneous.
Explanation:
According to Gibb's equation:
= Gibbs free energy
= enthalpy change
= entropy change
T = temperature in Kelvin
When = +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
For the given reaction 1: 
As for the reaction 1 , the value of Gibbs free energy is positive and thus the reaction 1 is non spontaneous.
The element is Am and since you lose e- there must be a postive charge. Am+6 is the symbol
<span>According to Mendeleyev-Klapeyron’s equation
pV = nRT,
where p = 160 atm V = 12 R -constant 0.0821 & T = 298 in Kelvin
Using given data, we can determine the amount of Helium gas:
n = pV/RT = (160â™12)/(0,0821â™298) = 78,48 (mol)
For atmospheric pressure (1 atm) and the same amount we can calculate the volume of tank, using previous equation:
V = nRT/p = (78,48â™0,0821â™298)/1 = 1920 (liters)
V = 1920 liters
Thus Answer is 1920 liters</span>
Answer:
- <em>The minimum number of photons that can be detected by the human eye is </em><u><em>6.03 × 10 ¹⁶</em></u><em> photons.</em>
Explanation:
The energy of one photon of light is related to the wavelength by the equation:
Where, E is the energy of one photon, h is the Planck's constant, c is the speed of light, and λ is the wavelength of the light.
You are given with <em>λ = 510 nm</em> (nanometers), which you must convert to m (meters), to use SI units ⇒ λ = 510 × 10⁻⁹ m.
The <em>physical constansts </em>needed are:
- Planck's constant, h = 6.63 × 10⁻³⁴ J.s
- Speed of light, in vacuum, c = 3.0 × 10⁻⁸ m/s
Now you can substitute in the formula can compute for the value of E:
- E = 6.63×10⁻³⁴ J.s × 3.0 × 10⁻⁸ m/s / (510×10⁻⁹ m) = 0.039 × 10⁻³³ J
Since, that is the energy of one photon of green light, to calculate the number of photons that can be detected by the human eye, you need to divide the amounf of <em>energy the human eye is able to detect, 2.35 × 10⁻¹⁸ J , </em>by the energy of a photon:
- number of photons = 2.35×10 ⁻¹⁸J / 0.039 × 10⁻³³ J/ photon
- number of photons = 60.3 × 10¹⁵ photons = 6.03 × 10¹⁶photons
