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Goryan [66]
1 year ago
9

Describe the many different forms of energy involved with stretching and releasing a rubber band. What other processes are simil

ar to this model?
Chemistry
2 answers:
Dafna1 [17]1 year ago
6 0

Answer:

Elastic potential energy------> kinetic energy --------> elastic potential energy

Explanation:

Elastic potential energy is the energy stored in a spiral spring. When a rubber band is stretched, this elastic potential energy is capable of doing work. This energy is just stored inside the rubber band and released when work is done by the rubber band.

Once the rubber band is released and it is in motion, the energy of the rubber is kinetic energy.

The system is similar to a simple pendulum.

Nadya [2.5K]1 year ago
5 0

Answer:

Conversion of kinetic energy to potential energy (chemo mechanical energy)

In the state of rest, the rubber is a tangled mass of long chained cross-linked polymer that due to their disorderliness are in a state of increased entropy. By pulling on the polymer, the applied kinetic energy stretches the polymer into straight chains, giving them order and reducing their entropy. The stretched rubber then has energy stored in the form of chemo mechanical energy which is a form of potential energy

Conversion of the stored potential energy in the stretched to kinetic energy

By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.

Explanation:

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Assuming equal concentrations of conjugate base and acid, which one of the following mixtures is suitable for making a buffer so
BartSMP [9]

Answer:

NH₃/NH₄Cl

Explanation:

We can calculate the pH of a buffer using the Henderson-Hasselbalch's equation.

pH=pKa+log\frac{[base]}{[acid]}

If the concentration of the acid is equal to that of the base, the pH will be equal to the pKa of the buffer. The optimum range of work of pH is pKa ± 1.

Let's consider the following buffers and their pKa.

  • CH₃COONa/CH3COOH (pKa = 4.74)
  • NH₃/NH₄Cl (pKa = 9.25)
  • NaOCl/HOCl (pKa = 7.49)
  • NaNO₂/HNO₂ (pKa = 3.35)
  • NaCl/HCl Not a buffer

The optimum buffer is NH₃/NH₄Cl.

4 0
1 year ago
A vessel contained N2, Ar, He, and Ne. The total pressure in the vessel was 987 torr. The partial pressures of nitrogen, argon,
xz_007 [3.2K]

Answer:

The partial pressure of neon in the vessel was 239 torr.

Explanation:

In all cases involving gas mixtures, the total gas pressure is related to the partial pressures, that is, the pressures of the individual gaseous components of the mixture. Put simply, the partial pressure of a gas is the pressure it exerts on a mixture of gases.

Dalton's law states that the total pressure of a mixture of gases is equal to the sum of the pressures that each gas would exert if it were alone. Then:

PT= P1 + P2 + P3 + P4…+ Pn

where n is the amount of gases present in the mixture.

In this case:

PT=PN₂ + PAr + PHe + PNe

where:

  • PT= 987 torr
  • PN₂= 44 torr
  • PAr= 486 torr
  • PHe= 218 torr
  • PNe= ?

Replacing:

987 torr= 44 torr + 486 torr + 218 torr + PNe

Solving:

987 torr= 748 torr + PNe

PNe= 987 torr - 748 torr

PNe= 239 torr

<u><em>The partial pressure of neon in the vessel was 239 torr.</em></u>

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2 years ago
Rust results from iron’s reaction to oxygen. An iron nail gains mass when it rusts. How does this reaction support the law of co
Olegator [25]

Answer:

Option (A). The mass of the rusted nail equals the mass of iron and the oxygen from the air it reacted with to form the rust.

5 0
1 year ago
Which species does not have a noble gas electron
lara31 [8.8K]
S, sulfur does not have a noble gas electron.
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2 years ago
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2.22x10^-3 would be the answer to the question 
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