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AfilCa [17]
2 years ago
5

Calculate the amount (in grams) of kcl present in 75.0 ml of 2.10 m kcl

Chemistry
1 answer:
Lera25 [3.4K]2 years ago
5 0
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol

74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl

:•)
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Explanation:

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The grease molecules are attracted more strongly towards each other as compared to water molecules. Also, water molecules are smaller in size hence, strong intermolecular force is required to break the hydrogen bonds of water molecule so that grease or oil molecules can enter the water molecule.

A soap molecule goes in between water and grease molecule and helps them to bind. The force for linkage between water and grease molecule through the soap molecule is weak london dispersion force.

The soap molecule has its salt end as ionic and water soluble. When grease or oil is added to the soap and water solution then the soap acts as an emulsifier. The soap forms miscelles of the non-polar tails and grease molecules are trapped between these miscelles. This miscelle is easily soluble in water hence, the grease is washed away.

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1 year ago
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8 0
2 years ago
You might be able to roughly estimate mass in a visual manner, but it could be easy to dismiss the fact that a mole or even a gr
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CO(g) + 2H2 (g) -> CH3OH(l)

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