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liberstina [14]
2 years ago
5

An atom of the element zinc has an atomic number of 30 and a mass number of 65. How many protons does an uncharged zinc atom hav

e?
30
35
65
95
Chemistry
2 answers:
notsponge [240]2 years ago
8 0
Z=atomic number=number of protons
Z=30=30 protons.

30

navik [9.2K]2 years ago
6 0

Answer : The correct option is, 30 protons

Explanation :

Element = Zinc

Atomic number = 30

Atomic mass number = 65

As we know that the atomic number is equal to the number of electrons and number of protons.

Atomic number = Number of electrons = Number of protons = 30

Number of neutrons = Atomic mass - Number of protons = 65 - 30 = 35

Therefore, the number of protons an uncharged zinc atom have 30 protons.

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Americium-242 has a half-life of 6 hours. If you started with 24 g and you now have 3 g, how much time
kogti [31]
How many times has it halved?

24/2 = 12
12/2 = 6
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It halved three times.
It halves once every 6 hours.

18 hours have passed.
7 0
2 years ago
How many moles of tungsten (W,183.85 g/lol are in 415 grams of tungsten?
vladimir1956 [14]

Given mass of tungsten, W = 415 g

Molar mass of tungsten, W = 183.85 g/mol

Calculating moles of tungsten from mass and molar mass:

415 g * \frac{1 mol}{183.85 g} = 2.26 mol W

7 0
1 year ago
How many moles of O2 would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 73.3% yi
Airida [17]

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Explanation:

4 0
2 years ago
Ammonia gas is compressed from 21°C and 200 kPa to 1000 kPa in an adiabatic compressor with an efficiency of 0.82. Estimate the
Evgen [1.6K]

Explanation:

It is known that efficiency is denoted by \eta.

The given data is as follows.

     \eta = 0.82,       T_{1} = (21 + 273) K = 294 K

     P_{1} = 200 kPa,     P_{2} = 1000 kPa

Therefore, calculate the final temperature as follows.

         \eta = \frac{T_{2} - T_{1}}{T_{2}}    

         0.82 = \frac{T_{2} - 294 K}{T_{2}}    

          T_{2} = 1633 K

Final temperature in degree celsius = (1633 - 273)^{o}C

                                                            = 1360^{o}C

Now, we will calculate the entropy as follows.

       \Delta S = nC_{v} ln \frac{T_{2}}{T_{1}} + nR ln \frac{P_{1}}{P_{2}}

For 1 mole,  \Delta S = C_{v} ln \frac{T_{2}}{T_{1}} + R ln \frac{P_{1}}{P_{2}}

It is known that for NH_{3} the value of C_{v} = 0.028 kJ/mol.

Therefore, putting the given values into the above formula as follows.

     \Delta S = C_{v} ln \frac{T_{2}}{T_{1}} + R ln \frac{P_{1}}{P_{2}}

                = 0.028 kJ/mol \times ln \frac{1633}{294} + 8.314 \times 10^{-3} kJ \times ln \frac{200}{1000}

                = 0.0346 kJ/mol

or,             = 34.6 J/mol             (as 1 kJ = 1000 J)

Therefore, entropy change of ammonia is 34.6 J/mol.

3 0
2 years ago
Discuss some of the biotic (living) and abiotic (nonliving) factors in the chimps’ ecosystem that affect their behavior.
Genrish500 [490]

Answer:

Diet:  fruit, leaves, bark, stems, seeds, eggs, insects, birds, small to medium sized primates - red tail monkeys, yellow baboons, bushbuck and warthogs.

Environmental Relationship - The chimpanzee keeps the plants it eats short, moves dirt around which helps things living in the dirt, keeps bird and small monkey populations that it eats from overpopulating.

Different biotic and abiotic factors affect why the chimps live where they do. (Spatial Relationships)

Explanation:

8 0
2 years ago
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