Answer:
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Explanation:
I hope the following explanation will help you a lot.
Answer: 19.4 mL Ba(OH)2
Explanation:
H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)
At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.
0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2
Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.
0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl
HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.
0.00892 mol OH- • (1 mol Ba(OH)2 / 2 mol OH-) • (1 L Ba(OH)2 / 0.230 M Ba(OH)2) = 0.0194 L = 19.4 mL Ba(OH)2
Answer:
After measuring the solute, Carl should first dissolve the solid in a small amount of DI water before diluting to the total volume.
Explanation:
To ensure that all the solute dissolves in the solution, first dissolve the solid in less than the total volume of solution needed.
Answer:
We have to add 2.30 L of oxygen gas
Explanation:
Step 1: Data given
Initial volume = 4.00 L
Number of moles oxygen gas= 0.864 moles
Temperature = constant
Number of moles of oxygen gas increased to 1.36 moles
Step 2: Calculate new volume
V1/n1 = V2/n2
⇒V1 = the initial volume of the vessel = 4.00 L
⇒n1 = the initial number of moles oxygen gas = 0.864 moles
⇒V2 = the nex volume of the vessel
⇒n2 = the increased number of moles oxygen gas = 1.36 moles
4.00L / 0.864 moles = V2 / 1.36 moles
V2 = 6.30 L
The new volume is 6.30 L
Step 3: Calculate the amount of oxygen gas we have to add
6.30 - 4.00 = 2.30 L
We have to add 2.30 L of oxygen gas
Answer:
If the angle of insolation is higher, then the temperature of the soil will be higher because it will receive more direct light.
Explanation:
