The ideal gas equation is;
PV = nRT; therefore making P the subject we get;
P = nRT/V
The total number of moles is 0.125 + 0.125 = 0.250 moles
Temperature in kelvin = 273.15 + 18 = 291.15 K
PV = nRT
P = (0.250 × 0.0821 )× 291.15 K ÷ (7.50 L) = 0.796 atm
Thus, the pressure in the container will be 0.796 atm
Well ask yourself why don't we count it in moles and you should get your answer.
Answer:
The pH of the solution is 8.
Explanation:
To which options are correct, let us determine the concentration of the hydroxide ion, [OH-] and the pH of the solution. This is illustrated below:
1. The concentration of the hydroxide ion, [OH-] can be obtained as follow:
pOH = –Log [OH-]
pOH = 6
6 = –Log [OH-]
–6 = Log [OH-]
[OH-] = Antilog (–6)
[OH-] = 1x10^–6 mol/L
2. The pH of the solution can be obtained as follow:
pH + pOH = 14
pOH = 6
pH + 6 = 14
pH = 14 – 6
pH = 8.
From the calculations made above,
[OH-] = 1x10^–6 mol/L
pH = 8.
Therefore, the correct answer is:
The pH of the solution is 8
A: The Equator To The Poles
The moles of oxygen that are produced when 26.5 mol of Al2O3 decomposes is 39.8 mol
<u>calculation</u>
<u> </u> 2Al2O3 + 4Al +3 O2
- use the mole ratio of Al2O3 to O2 to determine the moles of O2.
- that is from the equation above the mole ratio of Al2O3 : O2 is 2:3
- the moles of O2 is therefore=n 26.5 mol x3/2= 39.8 moles