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Lady_Fox [76]
2 years ago
13

You are experimenting on the effect of temperature on the rate of reaction between hydrochloric acid (HCl) and potassium iodide

(KI). When the reaction is completed at 273K there are approximately 250,000 collisions per mole of reactant. You run the experiment again at 350K. Which of the following would you expect to be the number of collisions recorded at 350K
A. 2000
B. 700,000
C. 0
D. 200,000
Chemistry
2 answers:
Oksana_A [137]2 years ago
7 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Collision is defines as the interaction of two bodies in motion. It depends on the kinetic energy of the particles. Number of collisions increases as kinetic energy of the particles increases.

Kinetic energy is the measure of temperature of the system. It is given by the equation:

E=\frac{3}{2}kT

where,

E = kinetic energy of the particles

k = Boltzmann constant

T = temperature

We are given:

Number of collisions at 273 K = 250,000

We need to find the number of collisions  at 350 K. As, the number of collisions increases as we increase the temperature. So, from the given options, the collisions at 350 K will be 700,000.

Hence, the correct answer is Option B.

erica [24]2 years ago
4 0

Answer is "B - 700,000".<span>

<span>Kinetic energy of a single particle (atom or molecule)<span> is directly proportional to its temperature according to the following equation.</span></span>
           KE = (3kT)/2

<span>Where </span>KE<span> is the kinetic energy of a single atom/molecule (</span>J<span>), </span>k<span> is the Boltzmann constant (</span>1.381 × 10</span>⁻²³ J/K<span>) and </span>T<span> is the temperature (</span>K<span>) </span><span>

When temperature increases, then the kinetic energy increases.

<span>If kinetic energy of atoms increases, then there will be more motions which create many collisions.</span></span>

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LenKa [72]

Answer:

Temperature at which molybdenum becomes superconducting is-272.25°C

Explanation:

Conductor are those hard substances which allows path of electric current through them. And super conductors are those hard substances which have resistance against the flow of electric current through them.

As given, molybdenum becomes superconducting at temperatures below 0.90 K.

Temperature in Kelvins can be converted in °C by relation:

T(°C)=273.15-T(K)

Molybdenum becomes superconducting in degrees Celsius.

T(°C)=273.15-0.90= -272.25 °C

Temperature at which molybdenum becomes superconducting is -272.25 °C

5 0
2 years ago
One ATP molecule's hydrolysis releases 7.3 kcal/mol of energy (∆G = −7.3 kcal/mol of energy). If it takes 2.1 kcal/mol of energy
Oxana [17]

Answer:

One ATP molecule's hydrolysis can move 3 ions of Sodium (Na+) across the menbrane.

Explanation:

As you can see, the energy provided by ATP is enough for moving 3 ions of Na+. Each ion needs +2.1 kcal/mol of energy.

If we multiply by 3 the energy for moving across the membrane= +6.3 kcal/mol

By adding the energy from ATP:

ΔGTotal=6.3-7.3= -1 kcal/mol

7 0
2 years ago
A bottle containing 1,665 g of sulfuric acid (H2SO4, 98.08 g/mol) was spilled in a laboratory. The emergency spill kit contained
Tamiku [17]

Answer:

A. Yes, there is more than enough sodium carbonate.

Explanation:

Hello,

In this case, based on the given reaction which is:

H_2SO_4(aq) + Na_2CO_3(s) \rightarrow  Na_2SO_4(aq) + CO_2(g) + H_2O(l)

By stoichiometry, one computes the grams of sodium carbonate that will neutralize 1,665 g of sulfuric acid as shown below:

1,665gH_2SO_4*\frac{1molH_2SO_4}{98.08gH_2SO_4}*\frac{1molNa_2CO_3}{1molH_2SO_4} *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}*\frac{1kgNa_2CO_3}{1000gNa_2CO_3}\\m_{Na_2CO_3}=1.80gNa_2CO_3

Thus, the available mass is 2.0 kg so 0.2 kg are in excess, therefore: A. Yes, there is more than enough sodium carbonate.

Best regards.

5 0
2 years ago
Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom
ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

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= 177.277amu to 3 decimal places.

6 0
2 years ago
6K + B2O3 → 3K2O + 2B
atroni [7]

Answer:

104.84 moles

Explanation:

Given data:

Moles of Boron produced = ?

Mass of B₂O₃ = 3650 g

Solution:

Chemical equation:

6K + B₂O₃    →    3K₂O + 2B

Number of moles of B₂O₃:

Number of moles = mass/ molar mass

Number of moles = 3650 g/ 69.63 g/mol

Number of moles = 52.42 mol

Now we will compare the moles of  B₂O₃ with B from balance chemical equation:

                 B₂O₃          :          B

                    1              :          2

                52.42         :        2×52.42 = 104.84

Thus from 3650 g of  B₂O₃  104.84 moles of boron will produced.

6 0
2 years ago
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