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2 years ago

Air tends to move from _____.

Chemistry

2 answers:

Mnenie [13.5K]2 years ago

8 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that equator is closer to the sun, therefore, region around the equator is warm. As a result, air near the equator is also warm.

Hence, molecules of air expand more rapidly whereas air near the poles is cold as poles are away from the sun.

Thus, we can conclude that air tends to move from the equator to the poles.

beks73 [17]2 years ago

4 0

A: The Equator To The Poles

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The table lists the chemical formulas or symbols of a few common substances. Which two substances are compounds? A) aluminum and

katrin [286]

D is the correct answer

every other option contains an element

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2 years ago

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Over-the-counter hydrogen peroxide solutions are 3% (w/v). What is this concentration in moles per liter?

Marina CMI [18]

1 ml of water weighs 1 gram so 1 liter (1000 ml) weighs 1000 grams. A 3% solution (3% = 0.03) of hydrogen peroxide (w/v) would contain 1000 grams x 0.03 or 30 grams. The chemical formula of hydrogen peroxide is H2O2 and a mole weighs 34.0147 grams/mole. So 30 grams of H2O2 divided by 34.0147 grams/mole equals 0.88 moles of H2O2. The concentration of a 3% (w/v) hydrogen peroxide solution therefore contains 30 grams of H202 (or 0.88 moles of H202) per in a liter of water (or 1000 grams H20) would thus be 0.88 moles H2O2 per liter (0.88 moles H2O2/l) .

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2 years ago

(A) A chemical reaction takes place in a container of cross-sectional area 100 cm2. As a result of the reaction, a piston is pus

balandron [24]

Answer:

(A) The work done by the system is -101.325J

(B) The workdone by the system is -90.75J

Explanation:

(A) Workdone = -PΔV

Given that A = 100cm2 = 0.01m2

distance d = 10cm = 0.1m

ΔV= Area × distance

ΔV= 0.01 ×0.1

ΔV = 0.001m3

P= external pressure = 1atm = 101325Pa

Workdone = -0.001 × 101325

W= - 101.325Pa m3

1Pam3 = 1J

Therefore W = - 101.325J

The work done on the system is -101.325J

(B) Workdone = -PΔV

Given that A = 50cm2 = 0.005m2

distance d = 15cm = 0.15m

ΔV= Area × distance

ΔV= 0.005×0.15

ΔV = 0.00075m3

P=121kPa = 121000Pa

W= - 121000 × 0.00075

W= -90.75Pa m3

1Pam3 = 1J

W = - 90.75J

The woekdone by the system is -90.75J

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2 years ago

84. Heavy water, D2O (molar mass = 20.03 g mol–1), can be separated from ordinary water, H2O (molar mass = 18.01), as a result o

ipn [44]

Answer:

relative rate of diffusion is 1.05

Explanation:

According to Graham's law of difussion:

Rate of diffusion is inversely proportional to the square root of molecular weight of a molecule.

For two given molecules:

$\frac{(rate)_{1}}{(rate)_{2}}=\frac{\sqrt{M_{2}} }{\sqrt{M_{1}}}$

The given molecules are

Water = 18.01

Heavy water =20.03

Thus the relative rate of diffusion will be:

$\frac{(rate)_{water}}{(rate)_{heavywater}}=\sqrt{ \frac{20.03}{18.01}}=1.05$

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2 years ago

The human eye is able to detect as little as 2.35 × 10–18 j of green light of wavelength 510 nm. Calculate the minimum number of

Mariulka [41]

Answer:

The minimum number of photons that can be detected by the human eye is 6.03 × 10 ¹⁶ photons.

Explanation:

The energy of one photon of light is related to the wavelength by the equation:

E = h×c/λ

Where, E is the energy of one photon, h is the Planck's constant, c is the speed of light, and λ is the wavelength of the light.

You are given with λ = 510 nm (nanometers), which you must convert to m (meters), to use SI units ⇒ λ = 510 × 10⁻⁹ m.

The physical constansts needed are:

Planck's constant, h = 6.63 × 10⁻³⁴ J.s

Speed of light, in vacuum, c = 3.0 × 10⁻⁸ m/s

Now you can substitute in the formula can compute for the value of E:

E = 6.63×10⁻³⁴ J.s × 3.0 × 10⁻⁸ m/s / (510×10⁻⁹ m) = 0.039 × 10⁻³³ J

Since, that is the energy of one photon of green light, to calculate the number of photons that can be detected by the human eye, you need to divide the amounf of energy the human eye is able to detect, 2.35 × 10⁻¹⁸ J , by the energy of a photon:

number of photons = 2.35×10 ⁻¹⁸J / 0.039 × 10⁻³³ J/ photon

number of photons = 60.3 × 10¹⁵ photons = 6.03 × 10¹⁶photons

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2 years ago