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NeX [460]
1 year ago
6

1. Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare the expected molarity of this solution to the a

ctual average molarity you measured in the standardization. What do you notice
Chemistry
1 answer:
geniusboy [140]1 year ago
8 0

Answer:

0.1M solution of NaOH

Explanation:

1 mole of NaOH - 40g

? moles - 1 g = 1/40 = 0.025 moles.

Molarity of 1.00g of NaOH in 0.25L (250 mL) = no. of moles/volume

= 0.025/0.25

= 0.1M.

You might be interested in
32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?
kotegsom [21]
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

5 0
1 year ago
Complete the following math problem and round your answer to the correct number of significant figures. Explain why your answer
BigorU [14]

Answer:

file link http/www.openfree

7 0
1 year ago
Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?
kramer

Answer:

Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?

a. Al (s)

b. H2O (l)

c. HCN (g)

d. CH3COOH (l)

e. C2H6 (g)

Explanation:

Entropy is the measure of the degree of disorderness.

In solids, the entropy is very less compared to liquids and gases.

The entropy order is:

solids<liquids<gases

Among the given substances, water in liquid form has a strong intermolecular H-bond.

So, it has also less entropy.

Next acetic acid.

Between the gases, HCN, and ethane, ethane has more entropy due to very weak intermolecular interactions.

HCN has slight H-bonding in IT.

Hence, the entropy order is:

Al(s) < CH3COOH (l) <H2O(l) < HCN(g) < C2H6(g)

7 0
1 year ago
Iodine is blue-black, crystalline, and solid. It sublimes to a violet-colored gas and reacts with aluminum and many other metals
Pepsi [2]

Answer:

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY

Explanation:

Chemical properties are visible through chemical reactions, in which the chemical identity changes to form new substances. On the other hand, physical properties are evident without a change in the identity of a substance.

<em />

<em>Which of these five properties are physical and which are chemical?</em>

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY
4 0
1 year ago
Consider the air over a city to be a box 100km on a side that reaches up to an altitude of 1.0 km. Clean air is blowing into the
Mariana [72]

Explanation:

It is known that equation for steady state concentration is as follows.

            C_{a} = \frac{QC}{Q + kV}

where,   Q = flow rate

              k = rate constant

              V = volume

              C = concentration of the entering air

Formula for volume of the box is as follows.

                 V = a^{2}h

                    = 100 \times 100 \times 1

                    = 10000 km^{3}

Now, expression to determine the discharge is as follows.

                  Q = Av

                      = 100 \times 1 \times \frac{4 m}{s} \times \frac{km}{1000 m}

                      = 0.4 km^{3}/s

And,    m (loading) = 10kg/s,

           k = 0.20/hr

as   1 km^3 = 10^{12} L (if u want kg/L as concentration)

Now, calculate the concentration present inside as follows.

     C_{in} = \frac{10kg/s}{0.4 km^3/s}

                 = 25 kg/km^3

Now, we will calculate the concentration present outwards as follows.

       C_{out} = {C_{in}}{(1 + k \times t)},

and,      t = \frac{V}{Q}

               = 25000 s or 6.94 hr

Hence,   C_{out} = \frac{25}{(1 + 0.20 \times 6.94)}

                         = 10.47 kg/km^3

Thus, we can conclude that the the steady-state concentration if the air is assumed to be completely mixed is C_{out} = 10.47 kg/km^3 and C_{in} = 25 kg/km^3 .

4 0
1 year ago
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