Answer: the original volume was 0.98L
Explanation:
V1 =?
T1 = 22k
V2 = 3.8L
T2 = 85k
V1 /T1 = V2 /T2
VI/22 = 3.8/85
V1 = 22 x (3.8/85)
V1 = 0.98L
The new molecule that is formed is an alcohol and is known as butanol. It has a chemical formula CH3CH2CH2CH2OH or C4H9<span>OH</span>. A molecule that has a hydroxyl functional group is an alcohol. It has isomers namely tert-butanol, 2-butanol and isobutanol.
The oxidation state of potassium ion K = +1
The oxidation state of oxygen ion O = -2
So, the oxidation state of O2 is = -2 x 2 = -4
Since, KBrO2 is neutral so,
(+1) + (x) + (-4) = Zero
-3 + X = Zero
So, X = +3
The oxidation state of individual bromine atom in KBrO2 is +3
Answer:
324.18 g/mol
Explanation:
Let the molecular mass of the antimalarial drug, Quinine is x g/mol
According to question,
Nitrogen present in the drug is 8.63% of x
So, mass of nitrogen = 
Also, according to the question,
2 atoms are present in 1 molecule of the drug.
Mass of nitrogen = 14.01 amu = 14.01 g/mol (grams for 1 mole)
So, mass of nitrogen = 14.01×2 = 28.02
These 2 must be equal so,

solving for x, we get:
<u>x = 324.18 g/mol</u>
Copper nitrate and nitric oxide are produced in this reaction.