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Elodia [21]
2 years ago
12

A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?

Chemistry
1 answer:
larisa [96]2 years ago
5 0

Answer:

Sn_2O

Explanation:

Hello,

In this case, given the mass of the sample and mass of tin we can compute the mass of oxygen via:

m_O=0.534g-0.500g=0.034g

Thus, by using the atomic bas of tin and oxygen we can compute their moles:

n_{Sn}=0.500gSn*\frac{1molSn}{118.8gSn} =0.00421mol\\\\n_O=0.034gO*\frac{1molO}{16gO}=0.002125mol

Next, we need to divide both moles by the moles of oxygen as those are the smallest in order to compute the subscript in the chemical reaction:

Sn=\frac{0.00421}{0.002125}=2\\ \\O=\frac{0.002125}{0.002125}= 1

Therefore, empirical formula of the oxide should be:

Sn_2O

Best regards.

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Mixing calcium carbonate and HCl. 
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 * Another physical change from liquid to vapor. You can cool down the resulting vapor and end up with the original water. So this is a bad choice. 
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 * This is a chemical change in that you're converting CuSO4 . 5H2O(s) into CuSO4 and H2O. So this too is a good choice. 
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A chemical reaction has occurred. So this is a good choice. 

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5 0
2 years ago
Read 2 more answers
An aspirin tablet contains 325.0 mg of aspirin, which has the molecular formula, C9H8O4. How many molecules of aspirin are in th
Inga [223]

Answer:

1.08X10²¹ molecules aspirin are in the tablet

Explanation:

Molar mass of aspirin is 180.15 g/m (C₉H₈O₄)

This data means that 1 mol weighs 180.15 g so:

325 mg = 0.325 g

If 180.15 g are contained in 1 mol of aspirin

0.325 g (which is the weight from the tablet) are contained in ...

(0.325 g  .1m)/180.15 g = 1.80x10⁻³ moles

1 mol has 6.02x10²³ molecules (NA)

1.80x10⁻³ moles are contained by ...

1.80x10⁻³ . NA = 1.08X10²¹ molecules

6 0
2 years ago
A solution was prepared by dissolving 200.0 g of KCI in 215 g of water.
Archy [21]

Answer:mole fraction of KCl = 0.18

Explanation:

no of moles of KCl     = Mass/Molar mass

where mass (weight) of KCl = 200.0g

molar mass of KC1= 74.6g/mol

                                                = 200/74.6   = 2.68 moles

no of moles of H2O = Mass/Molar mass

where mass (weight) of water = 215.0g

molar mass of water = 18.0g/mol

                                              = 215/18   = 11.94moles

mole fraction of KCl  = no of moles of KCl/(no of moles KCl + no of moles of H2O(water))

                                                = 2.68/(2.68+ 11.94)

                                                 = 2.68/14.62   = 0.18

5 0
2 years ago
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Norma-Jean [14]
1) Chemical reaction

C6H6 + Br2 ---> C6H5Br + HBr


2) Molar raios

1 mol C6H6 : 1 mol Br2 : 1 mol C6H5Br


3) Convert the data to moles

42.1 g of C6H6

molar mass of C6H6 = 6*12g/mol + 6*1g/mol = 78 g/mol

42.1 g / 78 g/mol = 0.54 mol


73.0 g of Br2


molar mass of Br2 = 2 * 79.9 g/mol = 159.8 g/mol

73.0 g / 159.8 g/mol = 0.46 mol of Br2


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4) Product

1 mol of Br2 (limiting reagent) yields 1 mole of C6H5Br, then you will obtain 0.46 mol of C6H5Br


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3 0
2 years ago
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Snezhnost [94]

Answer:

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Explanation:

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Mass % of water/Total mass % * 100 = 16.8 / 10.08 + 16.8 * 100 = 62.5%.  

8 0
2 years ago
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