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mel-nik [20]
2 years ago
7

A skateboard is pushed up a hill with a 90 N force to the left and experiences a gravitational force of 100 N to the right. (A)

Will accelerate to the left (B) Will accelerate to the right (C) Will not accelerate
Chemistry
2 answers:
Nat2105 [25]2 years ago
6 0
Since the 100 N to the right is greater than the 90 N, it will accelerate to the right.
Vilka [71]2 years ago
5 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Balanced force is defined as the forces that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the forces that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

A skateboard is pushed up a hill, the force applied on it is 90 N to the left.

The gravitational pull acting in the right on the skateboard is 100 N.

Net force acting on the object = 100- 90 = 10 N (acting in the right direction)

Hence, the correct answer is Option B.

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How many grams of caf2 would be needed to produce 8.41×10-1 moles of f2?
geniusboy [140]
Answer: 65.7 grams

Explanation:

1) ratio

Since 1 mole of CaF2 contains 1 mol of F2, the ratio is:

1 mol CaF2 : 1 mol F2

2) So, to produce 8.41 * 10^ -1` mol of F2 you need the same number of moles of CaF2.

3) use the formula:

mass in grams = molar mass * number of moles

molar mass of CaF2 = 40.1 g/mol + 2 * 19.0 g/mol = 78.1 g/mol

mass in grams = 78.1 g/mol * 8.41 * 10^ -1 mol = 65.7 grams
5 0
2 years ago
In the manufacture of paper, logs are cut into small chips, which are stirred into an alkaline solution that dissolves several o
Kitty [74]

Answer:

The estimated feed rate of logs is 14.3 logs/min.

Explanation:

The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.

That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.

Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.

To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

V=V_c+V_w\\\\M/\rho=M_c/\rho_c+Mw/\rho_w\\\\M/\rho=0.55*M/\rho_c+0.45*M/\rho_w\\\\1/\rho=0.55/\rho_c +0.45/\rho_w\\\\0.55/\rho_c=1/\rho-0.45/\rho_w\\\\0.55/\rho_c=1/(0.64*\rho_w)-0.45/\rho_w=(1/\rho_w)*(\frac{1}{0.64}-\frac{0.45}{1}  )\\\\0.55/\rho_c=1.1125/\rho_w\\\\\rho_c=\frac{0.55}{1.1125}*\rho_w= 0.494*\rho_w

The specific gravity of the wood chips is 0.494.

The average volume of a log is

V_l=(\pi*D^{2} /4)*L=(3.1416*\frac{8^{2}  \, in^{2} }{4} )*9ft*(\frac{12 in}{1ft})= 21714 in^{3}=12.57 ft^{3}

The weight of one log is

M=\rho*V=0.494*\rho_w*12.57  ft^{3}\\\\M=0.494*62.4\frac{lbm}{ft^{3} }*12.57ft^{3}\\\\M=387.5lbm

To provide 3617 ton/day of wood chips, we need

n=\frac{supply}{M_{log}}=\frac{3617 tons/day}{387.5 lbm}*\frac{2204lbm}{1ton}\\\\n=20573 logs/day=14.3 logs/min

The feed rate of logs is 14.3 logs/min.

7 0
2 years ago
Read 2 more answers
Show that the Newton has the units of mass times acceleration
Dimas [21]

F = ma = (kg)(m/s2) = kg ´ m/s2 N

hope this helps :D

7 0
2 years ago
The combustion of propane gas is used to fuel barbeque grills. If 4.65 moles of propane, C3H8, are burned in a grilling session,
Varvara68 [4.7K]

Answer:

<h3>moles of carbon dioxide=13.95mol</h3>

Explanation:

First wrie down the balance chemical reaction:

C_3H_8(g) + 5 O_2(g) \rightarrow 3 CO_2(g) + 4 H_2O(l)

Combustion reaction: The reacion in which hydrocarbon is burnt in the presence of oxygen gas and it releases heat and this reaction exothermic because heat of cumbustion is negative.

eg. burning of methane

By using unitry method,

From the above balanced reaction it is clearly that,

from 1 mole of propane 3 moles of carbon dioxide is formed

there fore,

from 4.65 mole of propane 3 \times 4.65 moles of carbon dioxide will form

moles of carbon dioxide=13.95mol

8 0
2 years ago
How many grams of KBr are required to make 550. mL of a 0.115 M KBr solution?
In-s [12.5K]

Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. We calculate as follows:

0.115 M = n mol KBr / .55 L solution

n = 0.06325 mol KBr

mass = 0.06325 mol KBr (119 g / mol) = 7.53 g KBr

4 0
2 years ago
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