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mel-nik [20]
2 years ago
7

A skateboard is pushed up a hill with a 90 N force to the left and experiences a gravitational force of 100 N to the right. (A)

Will accelerate to the left (B) Will accelerate to the right (C) Will not accelerate
Chemistry
2 answers:
Nat2105 [25]2 years ago
6 0
Since the 100 N to the right is greater than the 90 N, it will accelerate to the right.
Vilka [71]2 years ago
5 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Balanced force is defined as the forces that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the forces that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

A skateboard is pushed up a hill, the force applied on it is 90 N to the left.

The gravitational pull acting in the right on the skateboard is 100 N.

Net force acting on the object = 100- 90 = 10 N (acting in the right direction)

Hence, the correct answer is Option B.

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A solution was made in a 200.00 mL volumetric flask consisting of 18.00 mL of 2.125 M HCl and 0.4104 grams of CaCO3, followed by
____ [38]

Answer:

16.2mL of 0.1111M NaOH are used

Explanation:

<em>volumetric flask of 250.0mL</em>

As first, the HCl reacts with CaCO3 as follows:

2HCl + CaCO3 → H2O + CaCl2 + CO2

<em>Where 2 moles of HCl react with 1 mole of CaCO3</em>

To solve this question we must find the moles of each reactant in order to determine the moles of HCl that remains:

<em>Moles HCl:</em>

0.01800L * (2.125mol / L) = 0.03825 moles HCl

<em>Moles CaCO3 -Molar mass: 100.09g/mol-</em>

0.4104g * (1mol / 100.09g) = 0.00410 moles CaCO3

Moles HCl that reacts:

0.00410 moles CaCO3 * (2 mol HCl / 1 mol CaCO3) =

0.00820 moles HCl

Moles HCl that remains:

0.03825 moles HCl - 0.00820 moles HCl:

<em>0.03005 moles HCl remains </em>

The HCl reacts with NaOH as follows:

HCl + NaOH → H2O + NaCl

That means, to reach the equivalence point, the moles of NaOH that must be added = Moles HCl, in a sample of 15.00mL, the moles of HCl are:

0.03005 moles HCl * (15.0mL / 250.0mL) = 0.001803 moles HCl = Moles NaOH. The volume of 0.1111M NaOH is:

0.001803 moles NaOH * (1L / 0.1111moles) = 0.016L 0.1111M NaOH are required, that is:

<h3>16.2mL of 0.1111M NaOH are used</h3>
6 0
2 years ago
Calculate the number of chloride ions in 6.8 g of zinc chloride
Bumek [7]

Answer:

The correct answer is 0.300 * 10^23 ions.

Explanation:

Based on the given question, there is a need to find the number of chloride ions in the mentioned 6.8 grams of zinc chloride compound.  

The moles of zinc chloride (ZnCl2) is,  

= mass of zinc + 2 mass of chlorine

= 65.38 + 2 (35.45)

=65.38 + 70.90

= 136.28 grams (The molecular mass of zinc is 65.38 and the molecular mass of chlorine is 35.45)

Thus, 136.28 g of ZnCl2 contains 70.90 grams of chlorine

Therefore, 6.8 grams of ZnCl2 will comprise = (70.90/136.28) * 6.8

= 3.537 g of chlorine

70.90 g of Cl comprise 6.022*10^23 chlorine, thus, 3.537 g of Cl will comprise (6.022*10^23/70.90) * 3.537

= 0.300 * 10^23 ions of chlorine.  

3 0
2 years ago
The Rio Grande river flows through the South Texas Plains ecoregion of Texas. The river is a major source of water for cities an
mylen [45]

Answer:

What are the answer choices

Explanation:

7 0
1 year ago
Read 2 more answers
¿Cuántos moles de aluminio (AI) se necesitan para formar 3,7 mol de Al2O3? 4Al(s) + 302 (g) -&gt; 2A1203 (s) ​
tatuchka [14]

Answer:

3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3

Explanation:

8 0
2 years ago
Write a balanced half-reaction for the oxidation of liquid water H2O to aqueous hydrogen peroxide H2O2 in basic aqueous solution
nignag [31]

Answer : The balanced half-reaction in a basic solution will be,

2OH^-(aq)\rightarrow H_2O_2(aq)+2e^-  

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Rules for the balanced chemical equation in basic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion (OH^-) at that side where the less number of hydrogen are present.

Now balance the charge.

  • The half reaction is :

H_2O(l)\rightarrow H_2O_2(aq)

  • Now balance the oxygen atoms.

H_2O(l)\rightarrow H_2O_2(aq)+H_2O(l)

  • Now balance the hydrogen atoms.

H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)

  • Now balance the charge.

H_2O(l)+2OH^-(aq)\rightarrow H_2O_2(aq)+H_2O(l)+2e^-

The balanced half-reaction in a basic solution will be,

2OH^-(aq)\rightarrow H_2O_2(aq)+2e^-

7 0
2 years ago
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