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Tcecarenko [31]
1 year ago
6

Which statement correctly describes the location and charge of the electrons in an atom?

Chemistry
1 answer:
maxonik [38]1 year ago
3 0

Answer:

D

Explanation:

The electrons revolve around the nucleus and they contain negative charge

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Which is the first element to have 4d electrons in its electron configuration?
harkovskaia [24]
The first element to have 4d electrons in its electron configuration is Yttrium with an atomic number of 39 and the chemical symbol Y. The electron configuration of an atom refers to the distribution of its electrons in the atomic orbitals. These orbitals are represented by letters s,p,d,f and so on. The electron configuration of Yttrium is [Kr] 4d¹ 5s², wherein [Kr] refers to the electron configuration of the noble gas, Krypton.  
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A liquid that occupies a volume of 4.7 liters has a mass of 5.1 kilograms what is the density of the liquid in kg/L
kotykmax [81]
Divide each by 4.7 to get ur kg/L which is 1.085kg/1L
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1 year ago
Assuming ideal behavior, how many moles of argon would you need to fill a 14.0×12.0×10.0 ft room? assume atmospheric pressure of
Blababa [14]

We use the formula:

PV = nRT

First let us get the volume V:

volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3

Convert this to m^3:

volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3

 

n = PV / RT

n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm / mol K)

<span>n = 1,978.13 mol</span>

4 0
1 year ago
Gina wants to use models to better understand how the types of bonds in a molecule relate to the presence of geometric isomers.
vazorg [7]
The answer to this question is D! The ball and stick model! Hope this helps :)
8 0
1 year ago
Read 2 more answers
A 5.00 liter gas sample is collected at a temperature and pressure of 27.0 degree C and 1.20 atm. It is desired to transfer the
kipiarov [429]

Answer:

The temperature of the gas in the 3.00 liter container, must be 150K

Explanation:

Let's apply the Ideal Gas Law, to find out the moles

P . V = n . R . T

1,20 atm . 5L = n . 0,082 L.atm/mol.K . 300 K

(1,20 atm . 5L) /  (0,082 mol.K/L.atm . 300 K) = n

6/24,6 mol = n = 0,244 moles

We have the moles now, so let's find the temperature in our new conditions.

P . V = n . R . T

1 atm . 3L = 0,244 moles . 0,082 L.atm/mol.K . T° in K

(1 atm . 3L / 0,244 moles . 0,082 mol.K/L.atm) = T° in K

3/20,008 K = T° in K = 150K

3 0
1 year ago
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