I believe the correct answer would be that t<span>he change in enthalpy can be found by adding the enthalpies of the individual thermochemical reactions of a chemical reaction.</span> In Hess' Law, enthalpy is independent of the mechanism of the reaction. The enthalpy should be the sum of all the changes in the reaction.
Answer:
12.8seconds, 14.6seconds, 16.4seconds
Explanation:
the answers should b right as long as it is increasing in trend.
the reason why is bc of lower vol of hcl, and higher vol of water present. there is amount of hcl molecules present per volume. lesser chance of collisions, lower rate of successful collisions to poduce CO2
Answer : BaS
will be the precipitate which will be formed.
Explanation : When all the three solutions namely; 
are mixed together a white precipitate of BaS
is formed as a product in the solution along with the soluble by product of Ammonium nitrate which is 
Answer:
Option c → Tert-butanol
Explanation:
To solve this, you have to apply the concept of colligative property. In this case, freezing point depression.
The formula is:
ΔT = Kf . m . i
When we add particles of a certain solute, temperature of freezing of a solution will be lower thant the pure solvent.
i = Van't Hoff factor (ions particles that are dissolved in the solution)
At this case, the solute is nonvolatile, so i values 1.
ΔT = Difference between fussion T° of pure solvent - fussion T° of solution.
T° fussion paradichlorobenzene = 56 °C
T° fussion water = 0°
T° fussion tert-butanol = 25°
Water has the lowest fussion temperature and the paradichlorobenzene has the highest Kf. But the the terbutanol, has the highest Kf so this solvent will have the largest change in freezing point, when all the molalities are the same.
The simplified solubility of glucose at 30°C is 1.25 g/g of water. Considering that the density of water at 30°C is 1 g/mL, the equivalent mass of 400 mL of water is also 400g.
The concentration of the solution in water is,
550 g/400g of water = 1.375 g glucose / g of water
Since the concentration is higher compared to the solubility of glucose at the specified temperature, it can be said that the solution is SATURATED.
