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Fed [463]
2 years ago
13

The solubility of glucose at 30°C is 125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water a

t 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
Chemistry
2 answers:
nasty-shy [4]2 years ago
7 0

The solution is saturated.

At 30°C, 500 g of glucose will dissolve in 400 mL of solution.

Of the 550 g glucose added, only 500 g will dissolve and 50 g will precipitate out.

The amount of glucose in the solution can be increased by heating the solution because the solubility of solids tends to increase with temperature.

seraphim [82]2 years ago
4 0
The simplified solubility of glucose at 30°C is 1.25 g/g of water. Considering that the density of water at 30°C is 1 g/mL, the equivalent mass of 400 mL of water is also 400g. 

The concentration of the solution in water is,
                            550 g/400g of water = 1.375 g glucose / g of water

Since the concentration is higher compared to the solubility of glucose at the specified temperature, it can be said that the solution is SATURATED.
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PLZ HELP, GIVING BRAINLIEST!!
Pani-rosa [81]

Answer:

C. 2.000 M C6H12O6

Explanation:

Let us obtain the molarity of the solution.

Molar Mass of C6H12O6 = (12x6) + (12x1) + (16x6) = 72 + 12 + 96 = 180g/mol

Mass of C6H12O6 = 180g

Number of mole = Mass /Molar Mass

Number of mole of C6H12O6 = 180/180 = 1mole

Volume = 500mL = 500/1000 = 0.5L

Molarity = mole /Volume

Molarity = 1/0.5

Molarity = 2M

So the solution will be best labelled as 2M C6H12O6

6 0
1 year ago
During a titration the following data were collected. A 20.0 mL portion of solution of an unknown acid HX was titrated with 2.0
Dafna1 [17]

Answer:

The molarity of the acid HX is 6.0 M.

Explanation:

We determine the amount of moles of KOH used to neutralize the acid:

\frac{2.0moles_{KOH}}{1000ml} *60ml=0.12 moles KOH

Then, we calculate the amount of moles of acid:

0.12 moles KOH×\frac{1 mole HX}{1 moles KOH}=0.12 moles HX

The molarity of HX is:

\frac{0.12 moles HX}{20ml} *\frac{1000ml}{1l}=6.0 M

8 0
2 years ago
Why are metallic crystals malleable and ductile? A. The electrons are free floating, allowing them to move with the atoms when t
jok3333 [9.3K]

Answer:

D. The atoms are arranged with alternating positive and negative charges. When struck, the lattice shifts putting positives against positives and negatives against negatives.

Explanation:

Metallic crystals takes their properties as a result of metallic bonds in between the atoms.

Metallic bond is actually the attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by losing their outermost shell electrons this is by virtue of their low ionization energy.

Physical properties of metals such as malleability, ductility, electrical conductivity, etc can be accounted for by metallic bonds.

7 0
2 years ago
What is the volume of 43.7 g of helium at stp?
tankabanditka [31]
Answer is: volume of helium is 244.72 liters.
m(He) = 43.7 g.
n(He) = m(He) ÷ M(He).
n(He) = 43.7 g ÷ 4 g/mol.
n(He) = 10.925 mol.
V(He) = n(He) · n(He).
V(He) = 10.925 mol · 22.4 L/mol.
V(He) = 244.72 L.
Vm - molar volume at STP.
n - amount of substance.
0 0
2 years ago
Read 2 more answers
The data in the table below were obtained for the reaction: 2clo2 (aq) + 2 oh- (aq) --> clo3- (aq) + clo2- (aq) + h2o (l) exp
SVETLANKA909090 [29]
Lets organise the data given in the question
                [ClO₂] (m)       [OH⁻] (m)        initial rate (m/s)
                  <span>0.060              0.030               0.0248
</span><span>                  0.020              0.030               0.00276
</span><span>                  0.020              0.090                0.00828
rate equation as follows 
rate = k [</span>ClO₂]ᵃ [OH⁻]ᵇ
where k - rate constant 
we need to find order with respect to ClO₂ therefore lets take the 2 equations where OH⁻ is constant.
1) 0.00276 = k [0.020]ᵃ[0.030]ᵇ
2) 0.0248 = k [0.060]ᵃ[0.030]ᵇ
divide first equation from the second
0.0248/0.00276 = [0.060/0.020]ᵇ
8.99 = 3ᵇ
8.99 rounded off to 9
9 = 3ᵇ
b = 2
order with respect to ClO₂ is 2
3 0
1 year ago
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