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Fed [463]
2 years ago
13

The solubility of glucose at 30°C is 125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water a

t 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
Chemistry
2 answers:
nasty-shy [4]2 years ago
7 0

The solution is saturated.

At 30°C, 500 g of glucose will dissolve in 400 mL of solution.

Of the 550 g glucose added, only 500 g will dissolve and 50 g will precipitate out.

The amount of glucose in the solution can be increased by heating the solution because the solubility of solids tends to increase with temperature.

seraphim [82]2 years ago
4 0
The simplified solubility of glucose at 30°C is 1.25 g/g of water. Considering that the density of water at 30°C is 1 g/mL, the equivalent mass of 400 mL of water is also 400g. 

The concentration of the solution in water is,
                            550 g/400g of water = 1.375 g glucose / g of water

Since the concentration is higher compared to the solubility of glucose at the specified temperature, it can be said that the solution is SATURATED.
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Explanation:

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Read 2 more answers
What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig
Mashutka [201]

Answer:

P_H =2.86

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Explanation:

first write the equilibrium equaion ,

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assuming degree of dissociation \alpha =1/10;

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At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

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\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

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P_H= 3.86-1

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composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

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