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julia-pushkina [17]
1 year ago
13

Write down the dissolution equation for rubidium chromate dissolving in water. (Chromate is a polyatomic ion with the formula Cr

O42-.) If two moles of the ionic compound are dissolved, then how many moles of the CATION are present in the solution?
Chemistry
1 answer:
ycow [4]1 year ago
5 0

Answer:

Four moles of the cation

Explanation:

2Rb2CrO4(s)<--------> 4Rb^+(aq) + 2CrO4^2-(aq)

Now looking at the reaction equation, it can be seen that one mole of rubidium chromate contains two moles of rubidium ions and one mole of chromate ions.

The dissolution of two moles of rubidium chromate should then yield four moles of rubidium ions and two moles of chromate ions since the ratio of ions present is 2:1.

This explains the reaction equation written above for the dissolution of two moles of rubidium chromate as shown.

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A gas occupies a volume of 72 ml at 400 k and 800 torr. if the temperature drops to 200 k and the pressure changes to 400 torr,
satela [25.4K]
We are tasked to solve for the volume of the gas that occupies when pressure and temperature changes to 400 Torr and 200 Kelvin from Torr and 400 Kelvin. We can use ideal gas law assuming constant gas composition and close system. The solution is shown below:
P1V1 / T1 = P2V2 / T2
V2 = P1V1T2 / T1P2
V2 = 800*72*200 / 400*400
V2 = 72 ml

The answer for the volume is 72 ml.
7 0
2 years ago
Complete the reaction, which is part of the electron transport chain. The abbreviation Q represents coenzyme Q. Use the appropri
fredd [130]

Answer:

x = 2+

Explanation:

1) FADH2 + Q => FAD + QH2

Since H is added to Q

=> Reactant reduced is Q

(2) Balancing charges on both sides of the equation gives:

QH2 + 2 cyt c(Fe3+) => Q + 2 cyt c(Fe2+) + 2 H+

Thus x = 2+

7 0
2 years ago
What is the percent composition by mass of nitrogen in the compound N2H4 (gram-formula mass = 32 g/mol)?
Alex

Answer:

\large \boxed{93\, \% }

Explanation:

1. Calculate the molar mass of N₂H₄

2N = 2 × 14 = 28

4H = 2 ×  1  = <u>  4</u>

           Tot. = 32

2. Calculate the mass percent of N

\text{\% of element} = \dfrac{\text{mass of element}}{\text{mass of compound}} \times 100 \, \% = \dfrac{\text{28}}{\text{32}} \times 100 \, \% =\mathbf{88 \, \%}\\\\\text{The percentage of N in N$_{2}$H$_{4}$ is $\large \boxed{\mathbf{88\, \% }}$}}

3 0
2 years ago
Read 2 more answers
The density of a 50% solution of naoh is 1.525 g/ml. what volume of a solution that is 50% by weight naoh is required to make 0.
jolli1 [7]
We consider that the 50% given in this item is by volume. Molarity is the unit of concentration that takes into account the number of moles of the solute and the number of moles of the substance.

      number of moles of NaOH = (0.1 moles / L)(0.4 L)
                      n = 0.04 moles of NaOH

If we are to take the basis of 1 mL of 50% NaOH solution, 
  
                  (1 mL solution)(1.525 g/mL)(0.50) = 0.7625 g
The number of moles is,
                  0.7625 g NaOH x (1 mol / 40 g) = 0.01906 moles of NaOH

                volume of solution required = (0.04 moles of NaOH)(1 mL solution / 0.01906 moles of NaOH)
                 
                 volume of solution required = 2.09 mL

Answer: 2.09 mL
3 0
2 years ago
What atomic or hybrid orbitals make up the sigma bond between C2 and Cl in dichloroethylene, CH2CCl2 ? (C2 is the second carbon
inna [77]

Answer is:

1) orbital on C2 is sp2 hybrid orbitals and orbital on Cl is p atomic orbital.

Carbon atom is sp2 hybridized, it has three sp2 orbitals and one p orbital, they form four bonds. Three sp2 orbitals form three sigma bonds. Pi bonds are formed between two p orbitals on C1 and C2 atoms.

In sp2 hybridization the 2s orbital mixes with only two of the three available 2p orbitals.

2)  the approximate C1-C2-Cl bond angle is 120°.

4 0
2 years ago
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