answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sp2606 [1]
2 years ago
13

The end point of a titration is defined as the volume of titrant added, while the equivalence point is the volume required for c

omplete reaction with the analyte. By choosing the proper _____________, scientists can minimize the difference in these two numbers, allowing more accurate measurements in the lab.
Chemistry
1 answer:
natka813 [3]2 years ago
4 0

Answer:

indicator

Explanation:

Indicators are the weak organic dyes which shows different colors in acidic and basic mediums.

Due to the fact that a noticeable pH change occurs near the equivalence point of acid-base titrations, an indicator can be used to signal the end point of a titration.

Therefore, choosing the proper indicator, scientists can minimize the difference in these two numbers, allowing more accurate measurements in the lab.

You might be interested in
An increase in temperature will effect vapor pressure by:
-BARSIC- [3]

Answer: Increases.

Explanation:  As the temperature of a liquid or solid increases its vapor pressure also increases. Conversely, vapor pressure decreases as the temperature decreases.

5 0
2 years ago
Which procedure cannot be performed on a hot plate, requiring a Bunsen burner instead
ankoles [38]

Answer: Heating a crucible to remove water from a hydrate.

Explanation:

The options are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

d. Heating a crucible to remove water from a hydrate.

The procedure that can be performed on a hot plate are:

a. Heating a solvent to help a solute dissolve.

b. Heating an isolated solid to dry it.

c. Heating water to boiling for a water bath.

It should be noted that the hot plate cannot be used for heating of crucible in order to remove water from a hydrate. It is not advisable for someone to heat any silica or ceramic objects on a hot plate.

Therefore, heating a crucible to remove water from a hydrate is the correct option.

4 0
2 years ago
Water treatment plants commonly use chlorination to destroy bacteria. a byproduct is chloroform (chcl3), a suspected carcinogen
antiseptic1488 [7]
<span>100. ppb of chcl3 in drinking water means  100 g of CHCl3 in 1,000,0000,000 g of water

Molarity, M

M = number of moles of solute / volume of solution in liters

number of moles of solute = mass of CHCl3 / molar mass of CHCl3

molar mass of CHCl3 = 119.37 g/mol

number of moles of solute = 100 g / 119.37 g/mol = 0.838 mol

using density of water = 1 g/ ml => 1,000,000,000 g = 1,000,000 liters

M = 0.838 / 1,000,000 = 8.38 * 10^ - 7 M <----- answer

Molality, m

m = number of moles of solute / kg of solvent

number of moles of solute = 0.838

kg of solvent = kg of water = 1,000,000 kg

m = 0.838 moles / 1,000,000 kg = 8.38 * 10^ - 7 m <----- answer

mole fraction of solute, X solute

X solute = number of moles of solute / number of moles of solution

number of moles of solute = 0.838

number of moles of solution = number of moles of solute + number of moles of solvent

number of moles of solvent = mass of water / molar mass of water = 1,000,000,000 g / 18.01528 g/mol = 55,508,435 moles

number of moles of solution = 0.838 moles + 55,508,435 moles = 55,508,436 moles

X solute = 0.838 / 55,508,435 = 1.51 * 10 ^ - 8 <------ answer

mass percent, %

% = (mass of solute / mass of solution) * 100 = (100g / 1,000,000,100 g) * 100 =

% = 10 ^ - 6 % <------- answer
</span>
7 0
2 years ago
Read 2 more answers
A 23.2 g sample of an organic compound containing carbon, hydrogen and oxygen was burned in excess oxygen and yielded 52.8 g of
allochka39001 [22]

Answer:

The answer to your question is   C₃H₆O

Explanation:

Data

mass of sample = 23.2 g

mass of carbon dioxide = 52.8 g

mass of water = 21.6 g

empirical formula = ?

Process

1.- Calculate the mass and moles of carbon

                       44 g of CO₂ ---------------  12 g of C

                        52.8 g          ---------------  x

                        x = (52.8 x 12)/44

                        x = 633.6/44

                        x = 14.4 g of C

                        12 g of C ------------------  1 mol

                        14.4 g of C ---------------   x

                         x = (14.4 x 1)/(12)

                         x = 1.2 moles of C

2.- Calculate the grams and moles of Hydrogen

                         18 g of H₂O ---------------  2 g of H

                         21.6 g of H₂O -------------  x

                          x = (21.6 x 2) / 18

                         x = 2.4 g of H

                         1 g of H -------------------- 1 mol of H

                         2.4 g of H -----------------  x

                          x = (2.4 x 1)/1

                          x = 2.4 moles of H

3.- Calculate the grams and moles of Oxygen

Mass of Oxygen = 23.2 - 14.4 - 2.4

                           = 6.4 g

                         16 g of O ----------------  1 mol

                          6.4 g of O --------------  x

                          x = (6.4 x 1)/16

                          x = 0.4 moles of Oxygen

4.- Divide by the lowest number of moles

Carbon = 1.2 / 0.4 = 3

Hydrogen = 2.4/ 0.4 = 6

Oxygen = 0.4 / 0.4 = 1

5.- Write the empirical formula

                                C₃H₆O

8 0
2 years ago
Determine the number of moles in 4.21 x 10^23 molecules of CaCl2
Paha777 [63]
<h3>Answer:</h3>

0.699 mole CaCl₂

<h3>Explanation:</h3>

To get the number of moles we use the Avogadro's number.

Avogadro's number is 6.022 x 10^23.

But, 1 mole of a compound contains  6.022 x 10^23 molecules

In this case;

we are given 4.21 × 10^23 molecules of CaCl₂

Therefore, to get the number of moles

Moles = Number of molecules ÷ Avogadro's constant

          = 4.21 × 10^23 molecules ÷  6.022 x 10^23 molecules/mole

          = 0.699 mole CaCl₂

Hence, the number of moles is 0.699 mole of CaCl₂

7 0
2 years ago
Other questions:
  • A 36 gram sample of water has an initial temperature of 22 degrees Celsius after the sample absorbs 1200joules of heat energy th
    9·2 answers
  • How is the periodic law demonstrated in halogens
    10·2 answers
  • What is the stoichiometric ratio between BaCl2 and NaCl
    11·1 answer
  • A 75.00 g sample of a substance is analyzed and found to consist of 32.73 g phosphorus and 42.27 g oxygen. calculate the percent
    5·1 answer
  • From the options provided for each element below, choose the properties that it may have based on its location in the periodic t
    10·2 answers
  • The bond enthalpy of the C―N bond in the amide group of proteins can be treated as an average of C―N (276 kJ/mol) and C═N (615 k
    14·1 answer
  • A stock phenolphthalein solution was prepared by dissolving 0.050 g in a total volume of 100.0 ml. You place one drop (0.050 ml)
    13·1 answer
  • Suppose you are riding a bicycle. Describe a situation in which the bicycle has balanced forces acting on it. Describe a situati
    7·1 answer
  • Suggest why sodium and hydrogen ions do not diffuse at the same rate
    12·1 answer
  • A sample of baking soda contains 34.48 g of sodium, 1.51 g of hydrogen, 18.02 g of carbon, and 72.00 g of oxygen.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!