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hichkok12 [17]
2 years ago
15

Sean loves to go camping! When he goes camping, he uses a propane stove to cook all his meals. Propane's chemical formula is C3H

8. What type of reaction is being produced and what are the products when Sean uses his camping propane stove?
Chemistry
1 answer:
kotykmax [81]2 years ago
8 0

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O + heat

Explanation:

When Sean cook meals with propane he use a combustion reaction:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O + heat

When propane (C₃H₈) is reacted with oxygen (O₂) produces carbon dioxide (CO₂), water (H₂O) and heat.

Learn more about:

combustion reaction

brainly.com/question/13824679

#learnwithBrainly

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A mass spectrometer has determined the mass and abundances of all isotopes of an unknown element. The first isotope has a mass o
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The element that has a valence configuration of 5s25p6 is ________.
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Its period 5 from 5s25p6, with Xenon(54) as the noble gas.  2+6 = 8 electrons

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3 0
2 years ago
Aluminum oxide has a composition of 52.9% aluminum and 47.1% oxygen by mass. if 16.4 g of aluminum reacts with oxygen to form al
Dafna1 [17]
The balanced chemical reaction is written as:

4Al + 3O2 = 2Al2O3

To determine the mass of oxygen gas that would react with the given amount of aluminum metal, we use the initial amount and relate this amount to the ratio of the substances from the chemical reaction. We do as follows:

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Therefore, to completely react 16.4 grams of aluminum metal we need a minimum of 14.59 grams of oxygen gas.
3 0
2 years ago
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
2 years ago
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