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1 year ago

9

The diagrams show gases that are stored in two separate but similar containers.

2 answers:

Dmitriy789 [7]1 year ago

6 0

Answer:

The correct answer is C

Explanation:

Korolek [52]1 year ago

4 0

It's C I just took the test :)

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Which gas tank will empty first? acetylene (C2H2) oxygen (O2)

Monica [59]

The answer is oxygen. (02)

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2 years ago

Read 2 more answers

A sample of bismuth has a mass of 343g and volume of 35.0 cm3. what is the density of bismuth

elena-14-01-66 [18.8K]

I don’t think I could answer this sorry.........

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2 years ago

What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq) Use the

Leni [432]

Answer: $-3.8\times 10^{5}J$

Explanation:

$Mn+2Ag^{+}\rightarrow Mn^{2+}+2Ag$

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Mn^{2+}/Mn]}= -1.18V$

$E^0_{[Ag^{2+}/Ag]}=+0.80V$

$E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}$

$E^0=+0.80- (-1.18V)=1.98V$

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G^0=-nFE^0$

$\Delta G^0$ = gibbs free energy

n= no of electrons gained or lost = 2

F= faraday's constant

$E^0$ = standard emf = 1.98V

$\Delta G^0=-2\times 96500\times (1.98)=-3.8\times 10^{5}J$

Thus the value of $\Delta G^0$ is $-3.8\times 10^{5}J$

8 0

2 years ago

A gas is initially at a pressure of 0.43 atm, and a volume of 11.7 liters. Then the pressure is raised to 3.61 atm and the volum

lukranit [14]

Answer:

D. 91.98K

Explanation:

The General Gas Law equation is given by,

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

From the question,

the initial pressure,

$P_1 = 0.43 \: atm$

the initial volume,

$V_1 = 11.7 \: litres$

the final temperature,

$T_2=627K$

the final pressure,

$P_2=3.61atm$

the final volume,

$V_2=9.5litres$

Making

$T_1$

the subject of the expression, we obtain

$T_1= \frac{P_1V_1T_2}{P_2V_2}$

By substitution,

$T_1= \frac{0.43 \times11.7 \times627}{3.61 \times9.5}$

$T_1=91.980K$

Hence the initial temperature was 91.98 K

4 0

1 year ago

Read 2 more answers

A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the

vagabundo [1.1K]

Answer:

$n=3.0\times 10^{13}$

Explanation:

Charge on 1 electron = $-1.6\times 10^{-19}\ C$

The expression for charge is:-

$Charge=n\times q_e$

Given that:- Charge = $-4.8\times 10^{-6}\ C$

$-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})$

$n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}$

Total number of electrons, n = $3.0\times 10^{13}$

5 0

1 year ago