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Doss [256]
2 years ago
14

Three measurements of 34.5m, 38.4m, and 35.3m are taken. If the accepted value of the measurement is 36.7m, what is the percent

error for each measurement?
A. 5.99%, 4.63%, 3.81%
B. 5.09%, 4.06%, 3.08%
C. 5.55%, 4%, 3%
Chemistry
1 answer:
8_murik_8 [283]2 years ago
7 0

Answer:

A

Explanation:

% error in 1

36.7-34.5/36.7*100=5.99%

% error in 2

38.4-36.7/36.7*100=4.63℅

% error in 3

36.7-35.3/36.7*100=3.81%

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\Delta G_{rxn}=\Delta G^o+RT\ln Q

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[B] = concentration of B = 0.55 M

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-5980J/mol)+[(8.314J/mole.K)\times (310K)\times \ln (\frac{0.55}{1.8})

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