Answer:
PH₂ = 0.2 atm
C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
Explanation:
To determine the partial pressure of hydrogen gas (H2) in the mixture,
Partial pressure H₂ = Ptotal * xH₂
xH₂ = Mole fraction of H₂ = ∩H₂ / ( ∩H₂ + ∩O₂ + ∩N₂)
xH₂ = 0.01 / (0.01 + 0.015 + 0.025)
xH₂ = 0.01/0.05
xH₂ = 0.2
therefore
PH₂ = pT * xH₂
PH₂ = 1.0 atm * 0.2
PH₂ = 0.2 atm
so the correct option is C) About 0.20atm, because H2 comprises 20% of the total number of moles of gas.
Answer:
It is required answer.
Explanation:
Given that :
1. using balanced chemical equation:
ammonium acetate:
The balanced equation is:
NH₃ + H₂O ===> NH₄OH
when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.
When NH₄OH reacts with CH₃COOH then we get ammonium acetate and water
NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O
So, we can say that,
when we are adding an acid and a base together then we get the product of H₂O and given elements.
2. addition of barium hydroxide to sulfuric acid:
the balanced equation is
H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O
when acid and base reacts together than we get barium sulphate and water
when sulfuric acid and barium hydroxide.
Hence, it is required answer.
Since the temperature is constant, therefore, this problem can be solved based on Boyle's law.
Boyle's law states that: " At constant temperature, the pressure of a certain mass of gas is inversely proportional to its pressure".
This can be written as:
P1V1 = P2V2
where:
P1 is the initial pressure = 1 atm
V1 is the initial volume = 3.6 liters
P2 is the final pressure = 2.5 atm
V2 is the final volume that we need to calculate
Substitute with the givens in the above mentioned equation to get the final volume as follows:
P2V1 = P2V2
1(3.6) = 2.5V2
3.6 = 2.5V2
V2 = 3.6 / 2.5 = 1.44 liters
-OH is elctron donating -C=-N is electron withdrawing -O-CO-CH3 is electron withdrawing -N(CH3)2 is electron donating -C(CH3)3 is electron donating -CO-O-CH3 is electron withdrawing -CH(CH3)2 is electron donating -NO2 is electrong withdrawing -CH2
Answer:
a. 123.9°C
b.
c.
Explanation:
Hello, I'm attaching a picture with the numerical development of this exercise.
a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.
b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.
c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.
** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.
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