Question

A metallic object holds a charge of −4.8 × 10−6 C. What total number of electrons does this represent? (e = 1.6 × 10−19 C is the magnitude of the electronic charge.)

Answer 1

Answer:

$n=3.0\times 10^{13}$

Explanation:

Charge on 1 electron = $-1.6\times 10^{-19}\ C$

The expression for charge is:-

$Charge=n\times q_e$

Given that:- Charge = $-4.8\times 10^{-6}\ C$

$-4.8\times 10^{-6}=n\times (-1.6\times 10^{-19})$

$n=\frac{4.8\times 10^{-6}}{1.6\times 10^{-19}}=3.0\times 10^{13}$

Total number of electrons, n = $3.0\times 10^{13}$