4.4moles of oxygen atoms
Explanation:
Given parameters:
Mass of MgSO₄ = 132.2g
Unknown:
Number of moles of oxygen atoms = ?
Solution:
The number of moles is the quantity of substance that contains the avogadro's number of particles.
To solve for this;
Number of moles = 
Molar mass of MgSO₄ = 24 + 32 + 4(16) = 120g/mole
Number of moles =
= 1.1 moles
In
1 moles of MgSO₄ we have 4 moles of oxygen atoms
1.1 moles of MgSO₄ contains 4 x 1.1 moles = 4.4moles of oxygen atoms
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number of moles brainly.com/question/1841136
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We are tasked to solve for the volume of the gas that occupies when pressure and temperature changes to 400 Torr and 200 Kelvin from Torr and 400 Kelvin. We can use ideal gas law assuming constant gas composition and close system. The solution is shown below:
P1V1 / T1 = P2V2 / T2
V2 = P1V1T2 / T1P2
V2 = 800*72*200 / 400*400
V2 = 72 ml
The answer for the volume is 72 ml.
Thank you for posting your question here at brainly. Below are the choices that can be found elsewhere:
12.88 M
<span>0.1278 M </span>
<span>0.2000 M </span>
<span>0.5150 M
</span>
Below is the answer:
<span>5 times diluted (250/50),so 2.575/5=0.515 M
</span>
I hope it helps.
Answer:It is a mixture
Explanation:
If it is pure sugar it’s neither but if it has water it is a homogeneous mixture
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
4.8 g of Ca was added therefore mass present of Ca is 4.8 g
molar mass of Ca is 40 g/mol
molar mass is the mass of 1 mol of Ca
therefore if we substitute these values in the equation
number of moles of Ca = 4.8 g / 40 g/mol = 0.12 mol
0.12 mol of Ca is present
q2)
next we are asked to calculate the number of moles of water present
again we can use the same equation to find the number of moles of water
number of moles = mass present / molar mass
3.6 g of water is present
sum of the products of the molar masses of the individual elements by the number of atoms
H - 1 g/mol and O - 16 g/mol
molar mass of water = (1 g/mol x 2 ) + 16 g/mol = 18 g/mol
molar mass of H₂O is 18 g/mol
therefore number of moles of water = 3.6 g / 18 g/mol = 0.2 mol
0.2 mol of water is present