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1 year ago

Write a net ionic equation for the reaction that occurs when nickel(ii carbonate and excess hydrobromic acid (aq are combined.

1 answer:

7 0

First, we write the reaction equation:
NiCO₃ + 2HBr → NiBr₂ + H₂CO₃

Now, writing this in ionic form:
NiCO₃ + 2H⁺ + 2Br⁻ → NiBr₂ + 2H⁺ + CO₃⁻²

(NiCO₃ is insoluble so it does not dissociate in to ions very readily)

Overall equation:
NiCO₃ + 2Br⁻ → NiBr₂ + CO₃⁻²

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500 mL of He at 300 K is heated to 450 K. Find V2

ruslelena [56]

Answer:

V2 = 0.75 L

Explanation:

assumin ideal gas:

PV = RTn

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K..........(1)

⇒ V2/T2 = RN/P = K..........(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

8 0

1 year ago

How many moles of CO2 could fit in a 475 mL bag a -22° C and 855 mmHg?

Sergeeva-Olga [200]

Answer:

The amount of moles of CO₂ is 0.026 moles

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The equation known as the ideal gas equation explains the relationship between the four variables P (Pressure), V (Volume), T (Temperature) and n (Amount of substance). The ideal gas law is expressed mathematically as:

P*V = n*R*T

where P represents the pressure of the gas, V its volume, n the number of moles of gas (which must remain constant), R the constant of the gases and T the temperature of the gas.

In this case:

P= 855 mmHg
V= 475 mL= 0.475 L
n= ?

R= 62.36367 $\frac{mmHg*L}{mol*K}$

T= -22°C= 251 °K

Replacing:

855 mmHg*0.475 L=n*62.36367 $\frac{mmHg*L}{mol*K}$ *251 °K

Solving:

$n=\frac{855 mmHg*0.475 L}{62.36367 \frac{mmHg*L}{mol*K} *251 K}$

n= 0.026 moles

The amount of moles of CO₂ is 0.026 moles

4 0

2 years ago

A student has 7.05 g of zinc powder, 1.60 L of a 3.40 M calcium nitrate solution, and 1.50 L of a 1.60 M lead(II) nitrate soluti

trapecia [35]

Answer: Zinc will react with lead (II) nitrate solution.

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

General equation for single displacement reaction follows:

$A+BC\rightarrow AC+B$

When zinc is reacted with calcium nitrate, the reaction does not take place as zinc is less reactive than calcium. Zinc lies below in the series than calcium.

$Zn+Ca(NO_3)_2\rightarrow \text{No reaction}$

But, when zinc is reacted with lead (II) nitrate, the reaction do take place as zinc is more reactive than lead. Zinc lies above in the series than lead.

The chemical equation for the reaction of zinc and lead (II) nitrate follows:

$Zn+Pb(NO_3)_2\rightarrow Zn(NO_3)_2+Pb$