Answer:
726 torr
Explanation:
Generally, atmospheric pressure can be measured using a manometer which is in form of a U-shaped tube. In addition, 1 mm Hg is equivalent to 1 torr. Therefore, 752 torr is equivalent to 752 mm Hg. Therefore, the total pressure will be equivalent to the atmospheric pressure (mm Hg) + the mercury height.
In this case, the mercury height = -26 mm
Thus:
The helium pressure = 752 - 26 = 726 mm Hg
This is also equivalent to 726 torr
Mass of the friend sitting on the swing = 50 kg
Rate of acceleration = 4 m/s^2
The above information's are already given in the question. We need to utilize these information's in such a manner that the answer to the question can be determined easily.
We already know that
Force = Mass * acceleration.
This formula has to be used to find the force exerted.
Then
Force exerted = Mass of the friend * Acceleration
= (50 * 4) kg m/s^2
= 200 Newton
So the force exerted by me is 200 Newton. I hope the explanation and the procedure is clear to you and you are satisfied with it.
Answer:
4.16L
Explanation:
From the question given, we obtained the following data:
Molarity = 0.225 M
Number of mole of KI = 0.935mole
Volume =?
Molarity = mole / Volume
Volume = mole /Molarity
Volume = 0.935/0.225
Volume = 4.16L
Therefore, 4.16L of KI is needed.
Answer:
A = 674.33mmHg
B = 0.385atm
Explanation:
Both question A and B requires the application of pressure law which states that the pressure of a fixed mass of gas is directly proportional to its temperature provided that volume is kept constant.
Mathematically,
P = kT, k = P / T
P1 / T1 = P2 / T2 = P3 / T3 =.......= Pn/Tn
A)
Data:
P1 = 799mmHg
T1 = 50°C = (50 + 273.15) = 323.15K
P2 = ?
T2 = 273.15K
P1 / T1 = P2 / T2
Solve for P2
P2 = (P1 × T2) / T1
P2 = (799 × 273.15) / 323.15
P2 = 674.37mmHg
The final pressure is 674.37mmHg
B)
P1 = 0.470atm
T1 = 60°C = (60 + 273.15)K = 333.15K
P2 = ?
T2 = 273.15K
P1 / T1 = P2 / T2
Solve for P2,
P2 = (P1 × T2) / T1
P2 = (0.470 × 273.15) / 333.15
P2 = 0.385atm
The final pressure is 0.385atm
