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lesya [120]
2 years ago
5

How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?

Chemistry
1 answer:
Katyanochek1 [597]2 years ago
6 0

Answer:

4.16L

Explanation:

From the question given, we obtained the following data:

Molarity = 0.225 M

Number of mole of KI = 0.935mole

Volume =?

Molarity = mole / Volume

Volume = mole /Molarity

Volume = 0.935/0.225

Volume = 4.16L

Therefore, 4.16L of KI is needed.

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Na⁺,SO₄²⁻ is the answer

<h3>Further explanation </h3>

An ion is an atom or molecule that has a net electrical charge. There are many ions, one of them are sodium ion and sulfate ion.

SO₄²⁻ or Sulfate is a naturally occurring polyatomic ion that consist of a central sulfur atom surrounded by four oxygen atoms with occured widely in everyday life. Sodium ions are important for regulation of blood and body fluids, transmission of nerve impulses, heart activity, and certain metabolic functions.

Whereas Na⁺ or Sodium is a chemical element with the symbol Na and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sulfate ion is a very weak base. Therefore sulfate ion undergoes negligible hydrolysis in aqueous solution.

Enter the symbol of a sodium ion, Na⁺, followed by the formula of a sulfate ion, SO₄²⁻. Separate the ions with a comma only—spaces are not allowed. Express your answers as ions separated by a comma. Therefore the answer is: Na⁺,SO₄²⁻

Hope it helps!

<h3>Learn more</h3>
  1. Learn more about sodium ion brainly.com/question/6839866
  2. Learn more about sulfate ion brainly.com/question/2763823
  3. Learn more about ions brainly.com/question/11852357

<h3>Answer details</h3>

Grade:  9

Subject:  Chemistry

Chapter:  Introduction to Mastering Chemistry

Keywords: sodium ion, sulfate ion, ions, Chemistry, symbol

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Answer:

Follows are the solution to this question:

Explanation:

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Answer:

• pH = 3.0

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• pH = 3.61

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• pH = 1.40

Explanation:

El pH es una medida en química usada para determinar el grado de acidez o basicidad en una solución.

Se define como:

pH = -log₁₀ [H⁺]

<em>El - logaritmo de la concentración molar de H⁺</em>

<em />

Para las concentraciones de H⁺ dadas:

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