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Naddika [18.5K]
2 years ago
7

Which element in period 4 would have chemical properties similar to magnesium? 7. which metalloids would have chemical propertie

s similar to bromine? 8. which nonmetal would have chemical properties similar to tin? 9. which element in period 6 would have chemical properties similar to nitrogen? 10. which element is in period 1, group 18? helium?

Chemistry
2 answers:
azamat2 years ago
5 0
The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1. 

6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is <em>Calcium (Ca)</em>.

7. The elements that are striked through with the red slanting lines are the metalloids. All the elements to the left of the metalloids are metals. All the elements to the right are nonmetals. Bromine has a symbol of Br. Since At is a metalloid and located in the same group with Br, the <em>answer is Astatine (At).</em>

8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is <em>Carbon (C)</em>.

9. All the elements in period 6 would have similar properties. The answers could be: <em>Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi)</em>.

10. Period is row 1 and group 18 is the last column. <em>The answer is Helium (He).</em>

Bumek [7]2 years ago
4 0

6) Answer is: calcium (Ca).

Magnesium and calcium are in the group 2 of Periodic table. They have same number of valence electrons (two) and similar chemical properties.

Atomic number of magnesium (Mg) is 12, it means that it has 12 protons and 12 electrons.  

Electron configuration of magnesium atom: ₁₂Mg 1s² 2s² 2p⁶ 3s².

Atomic number of calcium is 20, it means that it has 20 protons and 20 electrons, so atom of calcium is neutral.

Electron configuration of calcium atom: ₂₀Ca 1s² 2s² 2p⁶ 3s² 3p⁶ 4s².

7) Answer is: astatine (At).

Bromine (Br) and astatine are in group 17 of Periodic table. They have same number of valence electrons (seven) and similar chemical properties.

In VIIA or group 17 (halogen elements) there are six elements: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At) and tennessin(Ts).

Astatine is a chemical element with symbol At and atomic number 85, it has 85 protons and 85 electrons. Valence electrons are in 6s and 6p orbitals.

Electron configuration of astatine atom: ₈₅At [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p⁵.

8) Answer is: carbon (C).

Tin (Sn) and carbon (C) are in group 14 of Periodic table. They have same number of valence electrons (four) and similar chemical properties.

Carbon  is a chemical element with symbol C and atomic number 6, which means it has 6 protons and six electrons. Valence electrons are in 2s and 2p orbitals.

Electron configuration of carbon atom: ₆C 1s² 2s² 2p².

9) Answer is: bizmuth (Bi).

Nitrogen (N) and bizmuth are in group 15 of Periodic table. They have same number of valence electrons (five) and similar chemical properties.

Bizmuth (Bi) has atomic number 83, it has 83 protons and 83 electrons. Valence electrons are in 6s and 6p orbitals.

Electron configuration of bizmuth atom: ₈₃Bi [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³.

Electron configuration for nitrogen: ₇N 1s² 2s² 2p³.

10) Answer is: helium (He).

Helium has atomic number 2, it has 2 protons and 2 electrons.

Electron configuration of helium atom: ₂He 1s².

Noble gases (group 18) are in group 18: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe) and radon (Rn). They have very low chemical reactivity.

Noble gases have very stable electron configuration and does not need to gain electrons, only when they gain energy.

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Answer:

Partial pressure of nitrogen gas is 0.98 bar.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gases.

P=p_{N_2}+p_{O_2}+p_{Ar}

p_{N_2}=P\times \chi_{N_2}

p_{O_2}=P\times \chi_{O_2}

p_{Ar}=P\times \chi_{Ar}

where,

P = total pressure = 3.9 bar

p_{N_2} = partial pressure of nitrogen gas  

p_{O_2} = partial pressure of oxygen gas  

p_{Ar} = partial pressure of argon gases  

\chi_{N_2} = Mole fraction of nitrogen gas  = 0.25

\chi_{O_2} = Mole fraction of oxygen gas  = 0.65

\chi_{Ar} = Mole fraction of argon gases = 0.10

Partial pressure of nitrogen gas :

p_{N_2}=P\times \chi_{N_2}=3.9 bar\times 0.25 =0.98 bar

Partial pressure of oxygen gas :

p_{N_2}=P\times \chi_{O_2}=3.9 bar\times 0.65=2.54 bar

Partial pressure of argon gas :

p_{N_2}=P\times \chi_{Ar}=3.9 bar\times 0.10=0.39 bar

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2 years ago
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a 4.0 L flask reacts to form SO3. If the temperature is 25ºC
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Answer : The pressure in the flask after reaction complete is, 2.4 atm

Explanation :

To calculate the pressure in the flask after reaction is complete we are using ideal gas equation.

PV=n_TRT\\\\P=(n_1+n_2)\times \frac{RT}{V}

where,

P = final pressure in the flask = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature = 25^oC=273+25=298K

V = volume = 4.0 L

n_1 = moles of SO_2 = 0.20 mol

n_2 = moles of O_2 = 0.20 mol

Now put all the given values in the above expression, we get:

P=(0.20+0.20)mol\times \frac{(0.0821L.atm/mol.K)\times (298K)}{4.0L}

P=2.4atm

Thus, the pressure in the flask after reaction complete is, 2.4 atm

5 0
1 year ago
The Lewis structures of four compounds are given. In the first molecule sufur is the central atom. There are two oxygen atoms bo
vesna_86 [32]

Answer:

Compound 1. Sulfur Dioxide

Compound 3. Dichloromethane

Compound 4. Phosphorus Trichloride

<em>(figure attached)</em>

Explanation:

Compound 1. Sulfur Dioxide

Polar compound

Through the Lewis structure it is confirmed that SO₂ is a polar compound, because it is an asymmetric compound having two regions of different polarity. The lower region having oxygen groups is more electronegative then the upper region.

Compound 2. Carbon Dioxide

Non polar Compound

Through the Lewis structure it is confirmed that CO₂ is a non polar compound, because it is a symmetric compound having two regions of same polarity. The left region and the right region both contains oxygen groups having same electronegativity.

Compound 3. Dichloromethane

Polar compound

Through the Lewis structure it is confirmed that CH₂Cl₂ is a polar compound, because it is an asymmetric compound having two regions of different polarity. Two chlorine atoms are attached to it and as we know that chlorine is a more electronegative element than hydrogen so it attracts the bonding pair of electrons towards itself which creates polarity.

Compound 4. Phosphorus Trichloride

Through the Lewis structure it is confirmed that PCl₃ is a polar compound, because three chlorine atoms attached to it and as we know that chlorine is a more electronegative element so it attracts the bonding pair of electrons towards itself which creates polarity.

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Calculate the Lattice Energy of KCl(s) given the following data using the Born-Haber cycle: ΔHsublimation K = 79.2 kJ/mol IE1 K
DanielleElmas [232]

Answer:

Explanation:

  The following equation relates to Born-Haber cycle

\triangle H_f = S + \frac{1}{2} B + IE_M - EA_X+ U_L

Where

\triangle H_f is enthalpy of formation

S is enthalpy of sublimation

B is bond enthalpy

IE_M is ionisation enthalpy of metal

EA_X is electron affinity of non metal atom

U_L is lattice energy

Substituting the given values we have

-435.7 = 79.2 + 1/2 x 242.8 + 418.7 - 348 +U_L

U_L = - 707 KJ / mol

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1 year ago
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