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patriot [66]
2 years ago
10

If element x forms the oxides xo and x2o3 the oxidation numbers of element x are

Chemistry
1 answer:
Deffense [45]2 years ago
3 0

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

XO

And:

X_2O_3

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

X^{+2}O^{-2}

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

X_2^{+3}O_3^{-2}

Thus, answer is b)+2 and +3

Best regards.

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List the salts in order from weakest to strongest lattice energy (most positive to most negative). magnesium chloride, barium ch
almond37 [142]

Answer: Option (6) is the correct answer.

Explanation:

Lattice energy is described as the energy released when formation of 1 mole of an ionic compound occurs due to the combination of its constituent ions.

Also, lattice energy is inversely proportional to the distance between the cation and anion. And, when we move down a group then there occurs an increase in the atomic radii of the atoms.

This means that smaller is the ionic distance between the cation and anion, more will be the lattice energy between the atoms.

Therefore, order from weakest to strongest lattice energy (most positive to most negative) for the given compounds is as follows.

 barium chloride < strontium chloride < calcium chloride < magnesium chloride

6 0
2 years ago
Tungsten is the metal used in the filaments of incandescent light bulbs. Naturally occurring tungsten consists of five isotopes
puteri [66]
Each of the Isotopic mass * its Abundance Sum together divide by 100. 
(179.946706*0.12 + 181.948206*26.5 + 182.9502245*14.3 + 183.9509326*30.64 + 185.954362*28.43  ) / 100 
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8 0
2 years ago
Read 2 more answers
The balanced equation shows how sodium chloride reacts with silver nitrate to form sodium nitrate and silver chloride. NaCl + Ag
Verdich [7]
<span>NaCl First calculate the molar mass of NaCl and AgNO3 by looking up the atomic weights of each element used in either compound Sodium = 22.989769 Chlorine = 35.453 Silver = 107.8682 Nitrogen = 14.0067 Oxygen = 15.999 Now multiply the atomic weight of each element by the number of times that element is in each compound and sum the results For NaCl 22.989769 + 35.453 = 58.44277 For AgNO3 107.8682 + 14.0067 + 3 * 15.999 = 169.8719 Now calculate how many moles of each substance by dividing the total mass by the molar mass For NaCl 4.00 g / 58.44277 g/mol = 0.068443 mol For AgNO3 10.00 g / 169.8719 g/mol = 0.058868 Looking at the balanced equation for the reaction, there is a 1 to 1 ratio in molecules for the reaction. Since there is a smaller number of moles of AgNO3 than there is of NaCl, that means that there will be some NaCl unreacted, so the excess reactant is NaCl</span>
8 0
2 years ago
For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data (Due to variations in th
CaHeK987 [17]

Answer:

a. 7278 K

b. 4.542 × 10⁻³¹

Explanation:

a.

Let´s consider the following reaction.

N₂(g) + O₂(g) ⇄ 2 NO(g)

The reaction is spontaneous when:

ΔG° < 0  [1]

Let's consider a second relation:

ΔG° = ΔH° - T × ΔS° [2]

Combining [1] and [2],

ΔH° - T × ΔS° < 0

ΔH° < T × ΔS°

T > ΔH°/ΔS°

T > (180.5 × 10³ J/mol)/(24.80 J/mol.K)

T >  7278 K

b.

First, we will calculate ΔG° at 25°C + 273.15 = 298 K

ΔG° = ΔH° - T × ΔS°

ΔG° = 180.5 kJ/mol - 298 K × 24.80 × 10⁻³ kJ/mol.K

ΔG° = 173.1 kJ/mol

We can calculate the equilibrium constant using the following expression.

ΔG° = - R × T × lnK

lnK = - ΔG° / R × T

lnK = - 173.1 × 10³ J/mol / (8.314 J/mol.K) × 298 K

K = 4.542 × 10⁻³¹

7 0
2 years ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
VLD [36.1K]

Answer:- 64015 J

Solution: There is 4250 mL of water in the calorimeter at 22.55 degree C.

density of water is 1 g per mL.

So, the mass of water = 4250mL(\frac{1g}{1mL})  = 4250 g

Final temperature of water after adding the hot copper bar to it is 26.15 degree C.

So, \Delta T for water = 26.15 - 22.55 = 3.60 degree C

Specific heat for water is 4.184 \frac{J}{g.^0C}

The heat gained by water is calculated by using the formula:

q=mc\Delta T

where, q is the heat energy, m is mass and c is specific heat.

Let's plug in the values in the formula and do the calculations:

q=4250g*\frac{4.184J}{g.^0C}*3.60^0C

q = 64015 J

So, 64015 J of heat is gained by the water.



5 0
2 years ago
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