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Mamont248 [21]
1 year ago
8

Aluminum metal reacts with aqueous cobalt(II) nitrate to form aqueous aluminum nitrate and cobalt metal. What is the stoichiomet

ric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients?
Chemistry
1 answer:
liraira [26]1 year ago
3 0

Answer:

The stoichiometric coefficient for aluminum is 2

Explanation:

Step 1: Data given

Aluminum metal = Al(s)

aqueous cobalt(II) nitrate = Co(NO3)2(aq)

aluminum nitrate = Al(NO3)3

cobalt metal = Co(s)

Step 2: The unbalanced equation

Al(s) + Co(NO3)2(aq) → Al(NO3)3(aq) + Co(s)

Step 3: Balancing the equation

On the left side we have 2x NO3 (in Co(NO3)2), on the right side we have 3x NO3 (in Al(NO3)3). To balance the amount of NO3 we have to multiply Co(NO3)2 on the left side by 3 and Al(NO3)3 on the right side by 2

Al(s) + 3Co(NO3)2(aq) → 2Al(NO3)3(aq) + Co(s)

On the left side we have 3x Co (in 3Co(NO3)2 ) and on the right we have 1x Co . To balance the amount of Co we have to multiply Co on the right by 3

Al(s) + 3Co(NO3)2(aq) → 2Al(NO3)3(aq) + 3Co(s)

On the right side we have 1x Al and on the right we have 2x Al, in (2Al(NO3)3 . To balance the amount of Al we have to multiply Al on the left by 2. Now the equation is balanced.

2Al(s) + 3Co(No3)2(aq) → 2Al(No3)3(aq) + 3Co(s)

The stoichiometric coefficient for aluminum is 2

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H A and H B are both weak acids in water, and HA is a stronger acid than HB. Which of the following statements is correct? Selec
lubasha [3.4K]

Answer:

B is a stronger base than A^-, which is a stronger base than H2O, which is a stronger base than CI^-

Explanation:

The general equation for each acid is:

HA(aq) + H2O(ac) ⇄ H3O+(aq) + A-(aq)

HB(aq) + H2O(ac) ⇄ H3O+(aq) + B-(aq)

When these acids dissociate into its ions in water they lose a proton (H+), so they are proton donors (acids) and H2O is the proton acceptor (base). This reaction produces a conjugate acid and a conjugate base.

Conjugate base is what remains of the acid molecule after it loses a proton:

HA = acid         A- Conjugate base

HB = acid         B- Conjugate base

A conjugate acid is formed when the proton is transferred to the base

H2O = base                H3O+ = Conjugate acid

The stronger acid will produce a weaker base. According to this, if HA is a stronger acid than HB, A- would be the weaker base (B- is the stronger base).

Compared with water, A- and B- are stronger bases because when they compete for a proton they have much greater affinity for H+ than water does and the equilibrium position will lie far to the left. (HA and HB are weak acids)

Finally Cl- is the weakest base because it comes after dissociation of HCl which is a strong acid

HCl(aq) + H2O → H3O+(aq) + Cl-(aq)

Note there is no double arrows, equilibrium lies far to the right. A strong acid yields a weak conjugate base it means one that has a low affinity for a proton.

4 0
2 years ago
What element is being oxidized in the following redox reaction?
gregori [183]

Answer:

C is the element thats has been oxidized.

Explanation:

MnO₄⁻ (aq)  +  H₂C₂O₄ (aq)  →  Mn²⁺ (aq)  +  CO₂(g)

This is a reaction where the manganese from the permanganate, it's reduced to Mn²⁺.

In the oxalic acid, this are the oxidation states:

H: +1

C: +3

O: -2

In the product side, in CO₂ the oxidation states are:

C: +4

O: -2

Carbon from the oxalate has increased the oxidation state, so it has been oxidized.

4 0
2 years ago
Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th
klasskru [66]

Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

7 0
1 year ago
A system fitted with a piston expands when it absorbs 52.7J of heat from the surroundings. The piston is working against a press
Allushta [10]

Answer: The initial volume of the system is 60.29 L.

Explanation:

According to the first law of thermodynamics,

      \Delta U = Q - W

As it is given that heat is being added to the system so, \Delta H will be positive. And, work done on the system is negative and work done by the system is positive.

So here, \Delta U = -107.4 J

                    Q = 52.7 J

                    P = 0.693 atm

And,     W = PdV

or,        W = P (V_{final} - V_{initial})

So,       \Delta U = Q - P (V_{final} - V_{initial})

            -107.4 J = 52.7 J - 0.693 \times 101.325 (63.2 - V)

            -160.1 = -43.79 - 70.21 (63.2 - V)

           63.2 - V = \frac{160.1 + 43.79}{70.21}

                  - V =  2.90 - 63.2

                     V = 60.29 L

Thus, we can conclude that the initial volume of the system is 60.29 L.

6 0
1 year ago
A weather balloon has a volume of 52.5 liters at a temperature of 295 K. The balloon is released and rises to an altitude where
Goryan [66]
So you have a balloon rising through the atmosphere. use the formula p1/v1=p2/v2 and add the variables into the equation, leaving 295/52.5=252/x. multiply 252 by 52.5 and divide that number by 295.
52.5*252=13230. divide by 295 =44.9 L
5 0
1 year ago
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