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vredina [299]
2 years ago
13

How much heat is required to increase the temperature of 10.0 grams of water 6.0oC? (The specific heat of water is 4.18 J/g x oC

)
Chemistry
1 answer:
Paraphin [41]2 years ago
5 0
250.8 J 

Approximately 250 J (A on Plato)
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A 5 mole sample of liquid acetone is converted to a gas at 75.0°C. If 628 J are required to raise the temperature of the liquid
Shkiper50 [21]
The total energy can be found by adding the different energies:
628 + 15,600 + 712
= 16.94 kJ
4 0
2 years ago
Which of these is a difference between a single skin cell and the skin tissue that covers an entire hand?
fgiga [73]

Answer:

c

Explanation:

the cells grow more than the tissue

7 0
2 years ago
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What is the maximum number of hydrogen atoms that can be covalently bonded in a molecule containing two carbon atoms?a) 2b) 3c)
aksik [14]

Answer:

           The correct answer is Option-D (6 Hydrogen atoms).

Explanation:

                  Carbon atom has a unique property of linking to it self and making a chain of carbon called as Catenation. In a molecule having two carbon atoms there must be a bond between the two carbon atoms. The bond can be saturated (single bond) or unsaturated (double or triple bond). But as the statement states maximum number of hydrogen atoms so, we will asume the bond between two carbon atoms to be single.

                  As carbon has four valence electrons so, it has the ability to make four single bonds. In given molecule each carbon has already made a single bond with another carbon therefore, each carbon is left with three more unpaired electrons which will make covalent bond with three hydrogen atoms each as shown in attached structure.

8 0
2 years ago
If a certain gas occupies a volume of 13 L when the applied pressure is 6.5 atm , find the pressure when the gas occupies a volu
Sav [38]
We should apply Boyle's Law here given initial pressure, initial volume and final volume.

P1V1= P2V2
(6.5 atm) (13 L) = P2 (3.3 L)

Solve for P2 on your calculator and that should get you to the answer.


5 0
2 years ago
Read 2 more answers
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
Read 2 more answers
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