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1 year ago

What is the mass, in grams, of 0.450 moles of Sb?

Chemistry

2 answers:

murzikaleks [220]1 year ago

7 0

Answer:

54.9 g

Explanation:

0.450 mol x 122g/mol

Allisa [31]1 year ago

4 0

Answer: 54.79 grams of Sb

Explanation: 0.450 moles Sb * 121.76 g Sb / 1 mole Sb = 54.79 g Sb

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What is the molarity of a naoh solution if 11.9 ml of a 0.220 m h2so4 solution is required to neutralize a 25.0-ml sample of the

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0.355M x 0.0282L= 0.01 moles of H2SO4. Remember sulphuric acid is diprotic so it will release 2 from each molecule.
So moles of protons = 0.01 x 2 = 0.02 moles of H+ 
For neutralization: moles H+ = moles OH- 
Therefore moles of NaOH = 0.02 
conc = moles / volume 
Conc NaOH = 0.02 / 0.025L = 0.8M

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1 year ago

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Germanium is a group 4A semiconductor. The addition of a dopant atom (group 3A element) that has fewer valence electrons than th

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Answer:

Doping with galium or indium will yield a p-type semiconductor while doping with arsenic, antimony or phosphorus will yield an n-type semiconductor.

Explanation:

Doping refers to improving the conductivity of a semiconductor by addition of impurities. A trivalent impurity leads to p-type semiconductor while a pentavalent impurity leads to an n-type semiconductor.

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1 year ago

Explain why the boiling point of water is a characteristic physical property, but the temperature and the volume of a glass of w

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Boiling and melting points are physical properties because they do not change the chemical nature of the substance whose properties you are measuring.

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1 year ago

How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?

Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate $NH_4NO_3$ in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

$Molality=\frac{n\times 1000}{W_s}$

where,

n= moles of solute

Moles of $NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles$

$W_s$ = weight of the solvent in g = ?

$0.452=\frac{0.348\times 1000}{W_s}$

$W_s=770g$

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate $NH_4NO_3$ in order to prepare a 0.452 m solution

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1 year ago

Be sure to answer all parts. Draw the structure of a compound of molecular formula C4H8O that has a signal in its 13C NMR spectr

GenaCL600 [577]

Answer:

The possible structures are ketone and aldehyde.

Explanation:

Number of double bonds of the given compound is calculated using the below formula.

$N_{db}=N_{c}+1-\frac{N_{H}+N_{Br}-N_{N}}{2}$

$N_{db}$ =Number of double bonds

$N_{c}$ = Number of carbon atoms

$N_{H}$ = Number of hydrogen atoms

$N_{N}$ = Number of nitrogen atoms

The number of double bonds in the given formula - $C_{4}H_{8}O$

$N_{db}= 4+1-\frac{8+0-0}{2}=1$

The number of double bonds in the compound is one.

Therefore, probable structures is as follows.

(In attachment)

The structures I and III are ruled out from the probable structures because the signal in 13C-NMR appears at greater than 160 ppm.

alkene compounds I and II shows signal less than 140 ppm.

Hence, the probable structures III and IV are given as follows.

The carbonyl of structure I appear at 202 and ketone group of IV appears at 208 in 13C, which are greater than 160.

Hence, the molecular formula of the compound $C_{4}H_{8}O$ having possible structure in which the signal appears at greater than 160 ppm are shown aw follows.

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2 years ago