Answer:
The correct option is: B) H₂0 and OH⁻ as a conjugate pair
Explanation:
According to Brønsted-Lowry theory, the<u> </u><u>acids</u><u> are the chemical substances that form a conjugate base by donating a proton</u> and <u>bases</u><u> are the chemical substances that form conjugate acid by accepting a proton.</u>
In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)
<u>According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.</u>
<u>Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.</u>
Answer:
Inference — The candle stayed lit longer because the plant gave off oxygen.
Observation — The candle went out when it was placed in a closed jar.
Observation — The candle stayed lit longer in closed jar when a plant was present.
Explanation:
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(If helpful)
Answer:
The answer to your question is below
Explanation:
Data
[HBr] = 0.045 M
[H⁺] = ?
[OH⁻] = ?
pH = ?
pOH = ?
Process
1.- Determine the [H⁺]
The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M
2.- Determine the pH
pH = -log[H⁺]
-Substitution
pH = -log[0.045]
-Result
pH = 1.35
3.- Determine the pOH
Formula
pH + pOH = 14
-Solve for pOH
pOH = 14 - pH
-Substitution
pOH = 14 - 1.35
-Result
pOH = 12.65
4.- Determine the [OH⁻]
pOH = -log[OH⁻]
-Solve for [OH⁻]
[OH⁻] = antilog(-pOH)
-Substitution
[OH⁻] = antilog (-12.65)
-Result
[OH⁻] = 2.22 x 10⁻¹³
Answer:
B
Explanation:
To write the electronic configuration of an element using the preceding noble gas configuration, we simply use the noble gas in the previous period of that particular element. We do not use the noble gas of that period in which the element belongs to but the one in the preceding group.
A is wrong
This is because the noble gas in the preceding period is krypton.
In fact, the electronic configuration is [Kr] 4d105s25p3
C is wrong
The noble gas in the last period here is Radon. The electronic configuration of Radium in fact is [Rn] 7s2
D is wrong
The noble gas in the last period before the period of uranium is Radon also. In fact, the electronic configuration of the element is [Rn] 5f36d17s2
B is correct, the actual electronic configuration of the element Cesium is [Xe] 6s1
